4 years ago

Between 1 and 100 how many two digit numbers are there that have 6 and 8 as factors?

Mathematics

1 answer:

Paul [167]4 years ago

4 0

Answer: 28 factors

Step-by-step explanation:

6: 6 12 18 24 30 36 42 48 54 60 66 72 78 84 90 96

8: 8 16 24 32 40 48 56 64 72 80 88 96

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An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.

brilliants [131]

The 15th term of the arithmetic sequence $a_{15} = 64$

Option B is correct

The nth term of an arithmetic sequence is given as:

$a_{n} = a + (n - 1)d$

The first value, a = 22

$a_8 = a+(8 - 1)d\\a_8 = a + 7d$

Since $a_8 = 43$

$43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3$

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Learn more here: brainly.com/question/24072079

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