Answer:
Step-by-step explanation:
First you have to calculate CB in order to use sin law to calculate ∠A
CB=![\sqrt{18.4^{2} -13.2^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B18.4%5E%7B2%7D%20-13.2%5E%7B2%7D%20%7D)
CB=12.8(correct to nearest tenth)
After that, use sin law to calculate ∠A,
or ![\frac{sin90}{18.4} =\frac{sinA}{12.8}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin90%7D%7B18.4%7D%20%3D%5Cfrac%7BsinA%7D%7B12.8%7D)
sinA=0.695...
A=44.079...
=44.1(corrext to the nearest tenth)
Is that clear enough for you?
Answer:
No solution
Step-by-step explanation:
As 6x on lhs and 2×3x on the rhs are equal and cancel each other
Answer:
55°
Step-by-step explanation:
35°+ 90° + ? =180°
? = 180° - 125°
= 55°
Answer: 36
Step-by-step explanation:
1) substitute x for 6
get f(-5)=6(1--5)= 6+30=46
In kilometers, the approximate distance to the earth's horizon from a point h meters above the surface can be determined by evaluating the expression
![d= \sqrt{12h}](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B12h%7D%20)
We are given the height h of a person from surface of sea level to be 350 m and we are to find the the distance to horizon d. Using the value in above expression we get:
Therefore, the approximate distance to the horizon for the person will be 64.81 km