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3 years ago

7

Range for the equation 2y=8-4x if the domain is (-2,-1,0,2,5)

1 answer:

Mazyrski [523]3 years ago

4 0

$2y=8-4x\ \ \ |divide\ both\ sides\ by\ 2\\\\y=4-2x$
Put numbers from {-2; -1; 0; 2; 5} to the equation instead of x:
$x=-2\to y=4-2\cdot(-2)=4+4=8\\\\x=-1\to y=4-2\cdot(-1)=4+2=6\\\\x=0\to y=4-2\cdot0=4\\\\x=1\to y=4-2\cdot1=4-2=2\\\\x=2\to y=4-2\cdot2=4-4=0$
We have the range: {0; 2; 4; 6; 8}.

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If the width and length of a rectangle are both increased by 10%, by what percent does the area of the rectangle increase?

S_A_V [24]

Answer:

10%

Step-by-step explanation:

We know Perimeter of rectangle

= 2 (Length + Width)

If width and length are increased by 10%

New length= L + 10/100L = (1.1) L

New width = W + 10/100W = (1.1) W

Perimeter = 2 [(1.1) L + (1.1) W]

Perimeter = 2 (1.1) (L + W)

Perimeter = (2.2) (L + W)

Increase in perimeter = 2.2 (L + W) - 2 (L + W)

The increase in Perimeter = 0.2 (L + W)

Percent increase

= 0.2 (L + W)/2 (L + W) × 100

= 0.2/2 × 100

= 0.1 × 100

= 10%

I hope this helped and if it did, please mark as Brainliest.

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Answer:

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The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

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3 years ago

Find the exact volume of the cylinder.<br> 1471 m3<br> 2871 m3<br> 5670 m3<br> 11271 m3

jenyasd209 [6]

Answer:

hmmmm........

Step-by-step explanation:

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volume of the cylinder is equal

to πr^h

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3 years ago