3 years ago

Anybody Know This. ?

Mathematics

2 answers:

Mashcka [7]3 years ago

6 0

I can’t see it it’s to blurry for me

Vinvika [58]3 years ago

4 0

Answer

Step-by-step explanation

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compared to last year, the population of Boom Town has increased by 10%. The population is now 6,600. What was the population la

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Answer:

Step-by-step explanation:

6600 x 10% = 60&$;#;,$:#&#>$

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mariarad [96]

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MARK AS BRAINLIEST

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Where is the center of the largest circle that you could draw inside a given triangle? . A.the point of concurrency of the media

juin [17]

The <em><u>correct answer</u></em> is:

C.the point of concurrency of the angle bisectors of the triangle

Explanation:

The largest circle that can be drawn inside a triangle is called an inscribed circle. The center of this circle is called the incenter.

The incenter is formed by the intersection of the angle bisectors of all 3 angles in the triangle.

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A line goes through the point (2, 4) and has a slope of 3/2. Which of the following points is also on the line? CHOOSE ALL THAT

damaskus [11]

Answer:

(4,7) and (0,1)

Step-by-step explanation:

(7-4)/(4-2) = 3/ 2, and (4-1)/(2-0) = 3/2.

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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

3 years ago