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Mariana [72]
3 years ago
9

What is the answer for 155,016 rounded to the nearest thousands?

Mathematics
1 answer:
Alona [7]3 years ago
7 0
To round off the value of 155, 016 to the nearest thousands, we can first elaborate the given to its expanded form which is:
100, 000 + 50, 000 + 5, 000 + 10 + 6 = 155, 016

<span>Since the nearest thousands is in the value is 5, 016 and the next number is 0 the number shall be 155, 000. Notice the rounding principles, 0-4.  </span>



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Factor the polynomial completely
aliina [53]

We have 2x^2-8.




First let us factor the 2 to obtain,


2(x^2-4)


We can now see clearly that the expression inside the parentheses is a difference of two squares.



We now write the 4 as 2². So that we obtain the expression,



2(x^2-2^2)


Recall that


a^2-b^2=(a+b)(a-b)



Hence our expression becomes,




2(x+2)(x-2)



Therefore, when factored completely,




2x^2-8=2(x+2)(x-2)






5 0
3 years ago
If the doctor’s office is 7 units from the zoo and 2 units from the park, which ordered pair could represent the location of the
s2008m [1.1K]

Answer:

(-4, -2) is the answer

Step-by-step explanation:

is you move 7 units down from the zoo you will see ur also 2 units from the park and the coordinates would be (-4, -2)

Hope this helps :)

6 0
3 years ago
Read 2 more answers
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
3 years ago
Help asap!!!<br><br><br><br><br><br> Please help
Pie
Why dont you try B.33 
4 0
3 years ago
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An urn contains 10 marbles: 4 red, 3 white, 2 blue, and 1 orange. (4 points) (a) What is the probability of drawing a marble tha
photoshop1234 [79]

Answer:

a) 0.70

b) 0.30

c) 12/45 =4/15

d) 2/45

Step-by-step explanation:

a) Prob of drawing a marble red or white = No of red and white marbles/total marbles

= 7/10 = 0.70

b)  Prob of drawing a marble neither red nor white = 1-7/10 = 0.30

c)  Prob of drawing two marble one red and one  white at the same time

= \frac{4C1 (3C1}{10C2 } =\frac{12}{45}

d) Prob of drawing two marble one blue and orange  white at the same time

= \frac{2C1 (1C1}{10C2 } =\frac{2}{45}

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3 years ago
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