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Andrei [34K]
3 years ago
5

What is the net force on this object?

Physics
2 answers:
Anna35 [415]3 years ago
3 0
:D HI YOUR ANSWER WOULD BE 8 NEWTONS TO DA RIGHT
22N to right + 14N to left 
Molodets [167]3 years ago
3 0

Answer:

8 Newtons

Explanation:

Net force is the vector sum of forces acting on a particle or body. It can also be regarded as a single force replaces the effect of the original forces on the particle's motion.

We calculate the net force, which is the the vector sum of all forces acting on an object

Given

F, norm = 20N

F, grav = 20N

F,app = 22N

F, frict = 14N

The net force here as stated earlier is calculated as sum of upward and forward forces minus sum of downward and backward forces.

So, Net force = (F, norm + F,app) - (F, frict + F, grav)

Substitute each value

Net force = (20N + 22N) - (20N + 14N)

Net force = 42N - 34N

Net force = 8N

Hence, the net force on the object is 8 Newtons

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4 years ago
A holiday ornament in the shape of a hollow sphere with mass M = 1.50×10−2 kg and radius R = 5.50×10−2 m is hung from a tree lim
pickupchik [31]

Answer:

T = 0.607 seconds

Explanation:

Given:

Mass, M = 1.50 × 10⁻² kg

Radius, R = 5.50 × 10⁻² m

Now,

the time period in terms of moment of inertia is given as:

T = 2\pi\sqrt\frac{I}{mgR}    .....................1

where, T is the time period

g is the acceleration due to gravity

I is the moment of inertia

Now,

Moment of inertia, I is given as:

I = \frac{5mR^{2}}{3}

on substituting the moment of inertia in the equation 1, we get

T = 2\pi\sqrt\frac{\frac{5mR^{2}}{3}}{mgR}

or

T = 2\pi\sqrt\frac{{5R}}{3g}

on substituting the valeus, we get

T = 2\pi\sqrt\frac{{5\times5.50\times10^{-2}}}{3\times9.8}

or

T = 0.607 seconds

Hence, the time period is 0.607 seconds

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3 years ago
Why are some starburst galaxies much brighter in infrared than they are in visible light?
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3 0
3 years ago
When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini
valkas [14]

Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

μ = 15/4.9

μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

4 0
4 years ago
Read 2 more answers
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