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1 year ago

Why are some starburst galaxies much brighter in infrared than they are in visible light?

1 answer:

4 0

Some starburst galaxies are much brighter in infrared radiation than they are in visible light because the dust surrounding the galaxies warms up and emits infrared light after absorbing visible light. Because of this, starburst galaxies produce up to 98% of their total energy in the infrared, making them some of the brightest infrared objects in the cosmos.

A sort of radiant energy that we experience as heat but that is invisible to human eyes is infrared radiation (IR), often known as infrared light. The sun and fire are two of the most prominent sources of IR radiation, however all objects in the cosmos release some of it.

To know more about infrared radiation go here

brainly.com/question/20779091

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The vertical component of the projectile motion of an object depends on which of these? initial velocity or angel of trajectory

SVEN [57.7K]

It depends on both of them.

In fact, the projectile begins its motion with an initial velocity of $v_0$ and an angle of $\alpha$ . On the y-axis (vertical direction), it is an accelerated motion with acceleration equal to -g (gravitational acceleration). The vertical velocity of the projectile at any time t is given by
$v_y (t) = v_0 sin \alpha + gt$
and as it can be seen, this depends on both initial velocity and angle.

3 0

3 years ago

A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M a

Yanka [14]

Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b. h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?

The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by

E = s/2ε₀[1 - z/√(z² + R²)]

So, the net force on the small plastic sphere of mass M and charge Q is

F = QE

F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² = (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² = √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

4 0

2 years ago

Which type of surface would most likely be the best reflector of electromagnetic energy?

Len [333]

<span>light colored and smooth surface would most likely be the best reflector of electromagnetic energy.Light, shiny surfaces are the best reflectors of radiation and they will allow the waves to reflect and bounce off rather than absorb. we can consider mirror as the example ,it will only reflect the light energy falling on them and it will not absorb. The darker coloured and rough surfaced substances will definitely absorb some amount of light falling on it. so light coloured smooth or shiny surfaced material would be the best reflector for electromagnetic energy.</span>

5 0

2 years ago

Most of our Solar system is composed of___

Bond [772]

Answer:

empty space

Explanation:

Our solar system comprises of the sun as the star, the planets, the dwarf planets, various moons, and plenty of asteroids, comets, and meteoroids. However, the majority part of the solar system consists of a void or empty space. These empty spaces basically composed of planetary dust and gas.

Hence, it can be concluded that Most of our Solar system is composed of "Empty Spaces."

5 0

2 years ago

A proton is projected into a magnetic field that is directed along the positive x axis. Find the direction of the magnetic force

bulgar [2K]

Te direction of the magnetic force for the velocity of the proton in the

-ve y direction will be +ve z direction.

As we know that the right-hand rule is based on the relation of magnetic fields and the forces that they exert on moving charges.When a charged particle moves under a magnetic field, it exerts a force on the particle, which is not in the same direction but different than the direction of the magnetic field.Under the right-hand rule, if we point our pointer finger in the direction of the charged particle is moving and the middle finger is representing the direction of the magnetic field then our thumb depicts the direction of the magnetic force which is exerted on the charged particle.

So, we are given that the direction of the velocity of the proton is in the negative y direction and the direction of the magnetic field is in the positive x direction, so the magnetic force is acting in the positive z direction.

To know more about the right-hand rule refer to the link brainly.com/question/9750730?referrer=searchResults.

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4 0

1 year ago