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White raven [17]
3 years ago
9

What is the solution to the system of equations? Use the substitution method. {y=2x+43x−6y=3

Mathematics
1 answer:
garri49 [273]3 years ago
5 0
We have that
<span>y=2x+4--------> equation 1
3x−6y=3-------> equation 2

step 1
</span>I substitute the value of y in equation 1 for the value of y in equation 2<span>
so
</span>3x−6*[2x+4]=3-------> 3x-12x-24=3
-9x=3+24
-9x=27------> 9x=-27
x=-27/9
x=-3

step 2
<span>I substitute the value of x in equation 1 to get the value of y</span>
y=2x+4--------> y=2*(-3)+4--------> y=-6+4
y=-2

the answer is 
the solution is the point (-3,-2)
x=-3
y=-2



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Answer: for -10 + 4 the answer is -6

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Step-by-step explanation:

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and for -7 - 11 you start at 7 and just go down (but the numbers get bigger) to -18 (-8, -9, -10, -11, -12, -13, -14, -15, -16, -17, -18)

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3 years ago
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pav-90 [236]

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3 years ago
PLEASE HELP!!!!! !!!!!!!!!!!!
valina [46]

Answer:

31.9secs

6,183.3m

Step-by-step explanation:

Given the equation that models the height expressed as;

h(t ) = -4.9t²+313t+269

At the the max g=height, the velocity is zero

dh/dt = 0

dh/dt = -9,8t+313

0 = -9.8t + 313

9.8t = 313

t = 313/9.8

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Hence it takes the rocket 31.9secs to reach the max height

Get the max height

Recall that h(t ) = -4.9t²+313t+269

h(31.9) = -4.9(31.9)²+313(31.9)+269

h(31.9) = -4,070.44+9,984.7+269

h(31.9) = 6,183.3m

Hence the maximum height reached is 6,183.3m

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uranmaximum [27]
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hope this helps
7 0
3 years ago
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