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hichkok12 [17]
3 years ago
13

When a fluid is heated, what changes occur?

Physics
1 answer:
lisov135 [29]3 years ago
8 0
The answer to this question is A. It becomes less dense and begins to rise.
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Charge is placed on two conducting spheres that are very far apart and connected by a long thin wire. The radius of the smaller
mrs_skeptik [129]

Answer:

surface charge density on each sphere is 440 \times 10^{-9} C

Explanation:

given data

radius of smaller sphere = 5 cm

radius of  larger sphere is 12 cm

electric field at surface of larger sphere = 660 kV/m = 660 × 1000 v/m

solution

we apply here electric field formula that is express as

E = (\frac{1}{4\pi\epsilon  })\times  (\frac{Q_{1} }{R^{2} } )    .................1

put here value

660000 = 9 \times 10^9 \times \frac{Q1}{0.12^2}  

Q1 = 1056 × 10^{-9}

and

here field inside a conductor is zero so that electric potential ( V ) is constant

\frac{Q{1} }{R} = \frac{Q{2} }{r}   ..................2

so Q2 will be

Q2 =  \frac{5}{12} \times 1056 \times 10^{-9}  

Q2 =  440 \times 10^{-9}  C

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3 years ago
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If your Stronger than Hisoka, and you know it, Clap your hands! Oh, wait.. That’s right! You don’t have any hands. Lol
ddd [48]

Answer:

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Explanation:

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What is an odometer?
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Answer:

It is a instrument used to measure the distance traveled by a vehicle.

Explanation:

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An emf is induced in a conducting loop of wire 1.22 m long as its shape is changed from square to circular. Find the average mag
Afina-wow [57]

Answer:

The induced emf in the loop is 7.35\times 10^{-4}\ V

Explanation:

Given that,

Length of the wire, L = 1.22 m

It changes its shape is changed from square to circular. Then the side of square be its circumference, 4a = L

4a = 1.22

a = 0.305 m

Area of square, A=a^2=(0.305)^2=0.0930\ m^2

Circumference of the loop,

C=2\pi r=L\\\\r=\dfrac{L}{2\pi}\\\\r=\dfrac{1.22}{2\pi}=0.194\ m

Area of circle,

A'=\pi r^2\\A'=\pi (0.194)^2\\\\A'=0.118\ m^2

The induced emf is given by :

\epsilon=\dfrac{\d\phi}{dt}\\\\\epsilon=\dfrac{\d(BA)}{dt}\\\\\epsilon=B\dfrac{A'-A}{t}\\\\\epsilon=0.125 \times \dfrac{0.118-0.0930}{4.25}\\\\\epsilon=7.35\times 10^{-4}\ V

So, the induced emf in the loop is 7.35\times 10^{-4}\ V

8 0
3 years ago
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