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svlad2 [7]
3 years ago
10

Two blocks with a mass of 2 kg collide in an elastic collision. The initial velocity of Block 1 is 10 m/s. Block 2 is traveling

at 2 m/s in the same direction as Block 1. What is the final momentum and kinetic energy of Block 2?
A final momentum: 2 kg x m/s, final kinetic energy: 1 J
B. final momentum: 20 kg x m/s, final kinetic energy: 10 J
C final momentum: 90 kg x m/s, final kinetic energy: 20 J
D. final momentum: 22 kg x m/s, final kinetic energy: 101 J​
Physics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

p = 20 kg•m/s

KE = 100 J

Explanation:

In an elastic collision of identical masses, the two masses will exchange momentums. Therefore Block 1 initially moving at 10 m/s will be moving at 2 m/s, and Block 2 will go from 2 m/s to 10 m/s

momentum = mv = 2(10) = 20 kg•m/s

KE = ½mv² = ½(2)10² = 100 J

Unfortunately, your answer selection does not have this answer as an option.

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Consider a hydrogen atom in the n = 1 state. The atom is placed in a uniform B field of magnitude 2.5 T. Calculate the energy di
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Answer:

E=29\times 10^{-5}eV

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

E^{+}=E+\mu B,

E^{-}=E-\mu B,

E^{0}=E

Here, E is the energy in the absence of electric field.

And

E^{+} and E^{-} are the highest and the lowest energies.

The difference of these energies

\Delta E=2\mu B

\mu=9.3\times 10^{-24}J/T is known as Bohr's magneton.

B=2.5 T,

Therefore,

\Delta E=2(9.3\times 10^{-24}J/T)\times 2.5 T\\\Delta E=46.5\times 10^{-24}J

Now,

Delta E=46.5\times 10^{-24}J(\frac{1eV}{1.6\times 10^{-9}J } )\\Delta E=29.05\times 10^{-5}eV\\Delta E\simeq29\times 10^{-5}eV

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is E=29\times 10^{-5}eV

6 0
3 years ago
What medium is often used to transfer computer information? a. Air c. Glass b. Water d. Optic fibers Please select the best answ
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3 years ago
A person drops a pebble of mass m1 from a height h, and it hits the floor with kinetic energy KE. The person drops another pebbl
Leona [35]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

<em>✔ We have: KE = PE (potential energy) </em>

<em>PE = m x g x h </em>

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\  \frac{m_1}{m_2\times 4} = 1 \\ \\  \frac{m_1}{m_2} = 4

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

 

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Explanation:

a chip on your shoulder is an example

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