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4vir4ik [10]
3 years ago
8

(True/False) According to Newton’s third law of motion, it is true that an object moving at a constant speed in a straight path

will continue to do so until a net force acts upon it.
Physics
1 answer:
algol133 years ago
7 0

The statement itself is true. But to be completely and compulsively correct, that's Newton's FIRST law of motion, not the third.

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Topics related to physics​
Bezzdna [24]

Answer:

There are many topics related to physics such as :

Kinematics

Dynamics

Light

Sound

7 0
2 years ago
The magnification is less than 1 what does it mean​
igomit [66]
If magnification is less than one it means the image is the same exact size as the object.
4 0
3 years ago
An egg is dropped from the top of the band hall. if the band hall is 25 m tall, determine the time it takes the egg to hit the f
Vera_Pavlovna [14]

Answer:

2.26 s

Explanation:

The following data were obtained from the question:

Height (h) = 25 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =..?

The time taken for the egg to hit the floor can be obtained as illustrated below:

h = ½gt²

25 = ½ × 9.8 × t²

25 = 4.9 × t²

Divide both side by 4.9

t² = 25 / 4.9

Take the square root of both side

t = √(25 / 4.9)

t = 2.26 s

Thus, it will take 2.26 s for the egg to hit the floor.

7 0
3 years ago
A river flows due east at 1.70 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
ad-work [718]

Answer:

a)

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)

the required distance is 40.98 m

Explanation:

Given that;

velocity of the river u = 1.70 m/s

velocity of boat v = 14.0 m/s

Now to get the velocity of the boat relative to shore;

( north of east), we say

a² + b² = c²

(1.70)² + (14.0)² = c²

2.89 + 196 = c²

198.89 = c²

c = √198.89

c = 14.1028 m/s  

tan∅ = v/u = 14 / 1.7 =  8.23529

∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east

Therefore, the velocity of the boat relative to shore is;

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)  

width of river = 340 m,

ow far downstream has the boat moved by the time it reaches the north shore in meters = ?

we say;

340sin( 90° - 83.0765°)

⇒ 340sin( 6.9235°)

= 40.98 m

Therefore, the required distance is 40.98 m

5 0
3 years ago
The answer<br> May someone please help me out.
Olin [163]

magnesium is an element

7 0
3 years ago
Read 2 more answers
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