Answer:
Explanation:
Given
Initial velocity u = 200m/s
Final velocity = 4m/s
Distance S = 4000m
Required
Acceleration
Substitute the given parameters into the formula
v² = u²+2as
4² = 200²+2a(4000)
16 = 40000+8000a
8000a = 16-40000
8000a = -39,984
a = - 39,984/8000
a = -4.998m/s²
Hence the acceleration is -4.998m/s²
Answer:
16 J
Explanation:
It is given that,
Work done, W = 2 J
A spring is stretched by 2.0 cm from its equilibrium length
We need to find how much more work will be required to stretch it an additional 4.0 cm.
Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :
The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.
So, the required work done is 16 J.
Answer:
The objects morion will remain the same
Explanation:
So, the average speed of the Cheetah is 17.6 m/s.
<h3>Introduction</h3>
Hello ! I'm Deva from Brainly Indonesia. This time, I will help regarding the average speed. The average speed is obtained from finding the average of the speeds that occur or can be detected from the division between distance and travel time. The average speed can be formulated by :
With the following condition :
- = average speed (m/s)
- s = shift or distance objects from initial movement (m)
- t = interval of the time (s)
<h3>Problem Solving</h3>
We know that :
- s = shift = 88 m
- t = interval of the time = 5 seconds
What was asked :
- = average speed = ... m/s
Step by step :
So, the average speed of the Cheetah is 17.6 m/s.
Answer:
the answer is abstinence.