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3 years ago

Which of the following STEM discoverers is known for inventing the circular saws used in sawmills? Babbitt Edison Gates Hawking

2 answers:

5 0

Among the STEM discoverers, the one who is known for the invention of the circular saws that are used in sawmills is Babbitt or better known as Sarah "Tabitha" Babbitt, an American inventor and Shaker tool maker. The answer to this is the first option. Hope this helps.

lara31 [8.8K]3 years ago

5 0

Answer:

Babbitt

Explanation:

Large circular saws are found in sawmills and are used for cutting wood in most applications. In 1813, Shaker's sister, Tabitha Babbitt invented the first circular saw, noted in a sawmill that was working on the spinning house in the Shaker Harvard community in Massachusetts, when she decided to invent an improvement for two-handed saws. men, for the production of lumber. Tabitha Babbitt is also known as the creator of an improved version of clipped nails, a new method of making false teeth, and a better spinning head.

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Wood is an example of a translucent material. True False

Svetradugi [14.3K]

False, wood is a solid structure that is not see through

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3 years ago

A racecar driver steps on the gas, and his racecar travels 20 meters in 2 seconds starting from rest. The acceleration of the ra

givi [52]

Answer:

2.5m/s^2

Explanation:

Step one:

given

distance = 20meters

time = 2 seconds

initial velocity u= 0m/s

let us solve for the final velocity

velocity = distance/time

velocity= 20/2

velocity= 10m/s

$v^2=u^2+2as\\\\10^2=0^2+2*a*20\\\\100=40a$

divide both sides by 40

$a= 100/40\\\\a=10/4\\\\a= 5/2\\\\a= 2.5m/s^2$

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3 years ago

Two spectators at a soccer game see, and a moment later hear, the ball being kicked on the playing field. The time delay for the

WINSTONCH [101]

Answer:

a)188.65m

b)154.35m

c)243.7m

Explanation:

Given data:

$t_A=0.55s$

$t_B=0.45s$

(a) The distance from the kicker to each of the 2 spectators is given by:

$d_A=v \times t_A$

where,

v= speed of sound

$t_A$ =time taken for the sound waves to reach the ears

$d_A=343\times 0.55=188.65$ m

(b) $d_B=v \times t_B$

where,

v= speed of sound

$t_B$ =time taken for the sound waves to reach the ears

$d_B=343\times 0.45=154.35m$

(c)As the angle b/w slight lines from the two spectators to the player is right angle,

hypotenuse=the distance b/w 2 spectators

and, the slight lines are the other 2 lines

$D^2=d_A^2+d_B^2\\D=\sqrt{188.65^2+154.35^2} \\D= 243.7m$

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3 years ago

An unstrained horizontal spring has a length of 0.31 m and a spring constant of 220 N/m. Two small charged objects are attached

Kruka [31]

The solution you should use is Hooke's law: F=-kx

It should have the same signs because they repel due to the stretch of the spring.

a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be
F = kx
270 N/m x 0.38 m = 102.6 N

b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force.

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3 years ago

A body of mass 2kg moves round a circle of radius 5m with a constant speed of 10m/s. Calculate the force toward the centre of th

antiseptic1488 [7]

Answer:

F = 5

Explanation:

F = m x v^2/r = 2 x 10^2/5 =200/5 = 40 (N)

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3 years ago