Ask question

Ask question

All categories

3 years ago

8

Psychological disorders:

2 answers:

dimulka [17.4K]3 years ago

4 0

Answer:

C. Can diminish a person's ability to live life.

Explanation:

A P E X

Olin [163]3 years ago

3 0

Answer:

Hmmm...It should be B.

Explanation:

You can't just assume you have depression just because of one day of sadness. You have to wait until you get more...factors or "symptoms", if so, you shouldn't diagnose yourself until you can confirm it by a mental health doctor (Not sure what it's called) or therapist.

××× If it's not B, I sincerely apologize! ×××

(This is just an example)

You might be interested in

Which of these cultures did NOT make major contributions to astronomy?

Svetlanka [38]

I can't particularly place what Icelandic contributed.

But every other culture contributed majorly.

So I would go for option b.

6 0

3 years ago

Problem: The frequency of an FM radio station is 89.3 MHz. Calculate its period. Part B: From the Library, select the general eq

vekshin1

Answer:

Time period, $T=1.11\times 10^{-8}\ s$

Explanation:

We have,

The frequency of an FM radio station is 89.3 MHz.

It is required to find the period of the wave.

The reciprocal of frequency is called time period of a wave. It can be given by :

$T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s$

So, the period of the wave is $1.11\times 10^{-8}\ s$ .

5 0

3 years ago

Yogi Berra is a famous New York Yankees relief pitcher. True False

Zolol [24]

False, he is a catcher, and he is in new york

4 0

3 years ago

Read 2 more answers

Qual a capacidade térmica de um objeto que, ao receber 10000 cal de energia, tem sua temperatura elevada de 25°C para 75°C?

Stolb23 [73]

Answer:

$200 cal/^{\circ}C$

Explanation:

When heat energy is supplied to an object, the temperature of the object increases according to the equation:

$Q=C\Delta T$

where

Q is the heat supplied

C is the heat capacity of the object

$\Delta T$ is the change in temperature

In this problem we have:

$Q=10,000 cal$ is the energy supplied

$\Delta T=75C-25C=50C$ is the change in temperature of the object

Therefore, the heat capacity of the object is:

$C=\frac{Q}{\Delta T}=\frac{10,000}{50}=200 cal/^{\circ}C$

6 0

3 years ago

Determine the focal length of a plano-concave lens (refractive index n =1.5) with 24 cm radius of curvature on its curve surface

tatyana61 [14]

Answer:

Option 3: -48 cm

Explanation:

We are given:

refractive index; n = 1.5

radius of curvature; r2 = 24 cm

Formula for the focal length is given as;

1/f = (n - 1) × [(1/r1) - (1/r2)]

As r1 tends to infinity, 1/r1 = 0

Thus,we now have;

1/f = (n - 1) × (-1/r2)

Plugging in the relevant values;

1/f = (1.5 - 1) × (-1/24)

1/f = -0.02083333333

f = -1/0.02083333333

f = -48 cm

3 0

2 years ago