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garri49 [273]
2 years ago
12

The bonds of the products store 22kJ more energy than the bonds of the reactants. How is energy conserved during this reaction?

Physics
1 answer:
babunello [35]2 years ago
8 0
The answer should be C.
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Which statement is true of AC current?. Select one of the options below as your answer:. . A.. It uses a battery as a power sour
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<span>The answer is B. It can be converted from high to low voltage and vice versa using transformers. That is why high voltages (tens or hundreds of kilovolts) is used to efficiently transfer electricity for large distances and then converted to 110-240V.

The answer can also be derived by elimination. [A] is not right because battery provides only Direct Current (DC). [C] is not right because high voltages are used for AC (from 110V to hundreds of kilovolts). [D] is not right because as the name Alternating Current suggests, the current is alternating in its direction. [E] is not right because DC was the first type of current invented.</span>
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3 years ago
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Give two ways in which the water vapour changes as it passes down the glass tube in the condenser
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3 years ago
The speed of propagation of electrical signals in a nerve cell depends on the diameter of the axon (nerve fiber). If the nerve c
gayaneshka [121]

Answer:

61 ms

Explanation:

Given that

Length of the nerve call connecting the spinal cord to your feet, s is 1.1 m

Speed of the impulse of the nerve, v = 18 m/s

Time taken by the nerve to travel the distance, t = ?

In solving this, we'd apply the very most basic formula in physics. Formula of speed, with respect to time and distance.

Speed, v = distance, s / time, t

time, t = distance, s / speed, v

time, t = 1.1 / 18

time, t = 0.061 s, converting to milliseconds, we have, time, t = 61 ms

6 0
3 years ago
Menghitung jisim molekul relatif dan jisim formula relatif​
kumpel [21]

Answer:

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7 0
3 years ago
Kinematics
leonid [27]

Answer:

a)

a = 2 [m/s^2]

b)

a = 1.6 [m/s^2]

c)

xt = 2100 [m]

Explanation:

In order to solve this problem we must use kinematics equations. But first we must identify what kind of movement is being studied.

a)

When the car moves from rest to 40 [m/s] by 20 [s], it has a uniformly accelerated movement, in this way we can calculate the acceleration by means of the following equation:

v_{f} = v_{i}+(a*t)

where:

Vf = final velocity = 40 [m/s]

Vi = initial velocity = 0 (starting from rest)

a = acceleration [m/s^2]

t = time = 20 [s]

40 = 0 + (a*20)

a = 2 [m/s^2]

The distance can be calculates as follows:

v_{f} ^{2} =  v_{i} ^{2}+(2*a*x)

where:

x1 = distance [m]

40^2 = 0 + (2*2*x1)

x1 = 400 [m]

Now the car maintains its speed of 40 [m/s] for 30 seconds, we must calculate the distance x2 by means of the following equation, it is important to emphasize that this movement is at a constant speed.

v = x2/t2

where:

x2 = distance [m]

t2 = 30 [s]

x2 = 40*30

x2 = 1200 [m]

b)

Immediately after a change of speed occurs, such that the previous final speed becomes the initial speed, the new Final speed corresponds to zero, since the car stops completely.

v_{f} = v_{i}-a*t

Note: the negative sign of the equation means that the car is stopping, i.e. slowing down.

0 = 40 - (a *25)

a = 40/25

a = 1.6 [m/s^2]

The distance can be calculates as follows:

v_{f} ^{2}  = v_{i} ^{2} -2*a*x3\\

0 = (40^2) - (2*1.6*x3)

x3 = 500 [m]

c)

Now we sum all the distances calculated:

xt = x1 + x2 + x3

xt = 400 + 1200 + 500

xt = 2100 [m]

8 0
3 years ago
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