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zimovet [89]
2 years ago
6

The first step in responding to any sports injury is to __________.

Physics
2 answers:
True [87]2 years ago
7 0

Answer:

A

Explanation:

  • The first step in responding to an injury in sports is to remove the danger that led to the injury
  • B cannot be correct because if an athlete suffers a broken leg you don't check their air ways primarily
  • C is also not right as that is only when the player is unconscious
  • D is not right as that is the result of only a very life-threatening injury
  • A is the right answer
melamori03 [73]2 years ago
4 0

Answer:

remove the danger that lead to injury

Explanation:

The best way is

  • spot the reason for injury
  • Then try best to remove that cause as fast as possible.
  • Then spot the place of body where injury happened
  • NOW treat for that
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A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?
Triss [41]

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

H_m = \frac{u^2sin^2 \theta}{2g}

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta  = sin^{-1}(0.2123)\\\\\theta  = 12.26^0

Therefore, the angle of projection is 12.26⁰.

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2 years ago
What is the name of the phenomenon that causes observed light from a star to change its wavelength?
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Explanation:

hoped this helped have a good day :)

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The mass of a car is 2,400 kg and its momentum is 22,240 kg<br> m/s. What is its velocity?
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Answer:

9.27

Explanation:

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Answer:

A negative charge, if free to move in an electric field, will move from a low potential point to a high potential point. To move a positive charge against the electric field, work has to be done by you or a force external to the field.

Explanation:

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Answer:

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