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1 year ago

6

The first step in responding to any sports injury is to __________.

2 answers:

True [87]1 year ago

7 0

Answer:

A

Explanation:

The first step in responding to an injury in sports is to remove the danger that led to the injury
B cannot be correct because if an athlete suffers a broken leg you don't check their air ways primarily
C is also not right as that is only when the player is unconscious
D is not right as that is the result of only a very life-threatening injury
A is the right answer

melamori03 [73]1 year ago

4 0

Answer:

remove the danger that lead to injury

Explanation:

The best way is

spot the reason for injury
Then try best to remove that cause as fast as possible.
Then spot the place of body where injury happened
NOW treat for that

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The electrons of carbon and hydrogen are _____________ in this molecule of methane.

nlexa [21]

Answer:

The answer is C

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3 years ago

Radio devices are used for communication in space. Why

Elena-2011 [213]

Because radio waves can travel in space but sound waves cannot.

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3 years ago

A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. Complete the following statemen

Eva8 [605]

Answer:

Keeping the speed fixed and decreasing the radius by a factor of 4

Explanation:

A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. The centripetal acceleration is given by :

$a=\dfrac{v^2}{R}$

We need to find how the "centripetal acceleration of the ball can be increased by a factor of 4"

It can be done by keeping the speed fixed and decreasing the radius by a factor of 4 such that,

R' = R/4

New centripetal acceleration will be,

$a'=\dfrac{v^2}{R'}$

$a'=\dfrac{v^2}{R/4}$

$a'=4\times \dfrac{v^2}{R}$

$a'=4\times a$

So, the centripetal acceleration of the ball can be increased by a factor of 4.

7 0

3 years ago

un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en l

Dmitriy789 [7]

Answer:

Acceleration = 5.77 m/s²

Distance cover in 13 seconds = 487.56 meter

Explanation:

Given:

Final velocity of mobile device = 75 m/s

initial velocity of mobile device = 0 m/s

Time taken = 13 seconds

Find:

Acceleration

Distance cover in 13 seconds

Computation:

v = u + at

75 = 0 + (a)(13)

13a = 75

a = 5.77

Acceleration = 5.77 m/s²

s = ut + (1/2)(a)(t²)

s = (0)(t) + (1/2)(5.77)(13²)

Distance cover in 13 seconds = 487.56 meter

8 0

2 years ago

URGENT!! <br>Question in attachment. <br>thanks

Roman55 [17]

Answer:9

Explanation:beacause

6 0

3 years ago

Read 2 more answers