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3 years ago

What is one way a rift valley can form?

2 answers:

8 0

A rift valley can form when a chunk of the earths crust is moved downward between two parallel faults. In other words, when the crust is expanded or spreads.

Nady [450]3 years ago

3 0

Hello.

A rift valley can form by tectonic plates moving apart. They are formed between mountions and a <span>a geologic </span>rift.

Have a nice day

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The flow rate in a firehose is 0.524 m3/s. It is able to shoot water to the top of a building 40.4 m tall, but not higher. You r

Marrrta [24]

Answer:

A fire hose must be able to shoot water to the top of a building 35.0 m tall ... Water enters this hose at a steady rate of 0.500 m3/s and shoots out of a round nozzle. ... I know that Flow rate=0.500 m3/s=A*V. I know the pressure needed to ... The first equation has no potential while the second has no kinetic.

Explanation:

3 0

3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

$a=\frac{qE}{m}$

Substitute the values of q, E and m in the above equation.

$a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }$

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

6 0

3 years ago

a student pushes a 0.500 kg trolley along a frictionless surface and accelerates it from rest to 4m/s. how much kinetic energy d

aalyn [17]

mass=m=0.5kg
velocity=4m/s

$\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2$

$\\ \sf\longmapsto KE=\dfrac{1}{2}(0.5)(4)^2$

$\\ \sf\longmapsto KE=0.25(16)$

$\\ \sf\longmapsto KE=4J$

7 0

2 years ago

The pic says everything, thank you !

Alenkasestr [34]

Answer:

1/5 or .2

Explanation:

you put miles over seconds 3/15 then simplify to 1/5 to get miles per second

4 0

3 years ago

A musician on a unicycle is riding at a steady 6.2 m/s while playing their well tuned oboe at an A above middle C (440 Hz). They

Verizon [17]

Answer:

The frequency of the beat is $f_t = 8Hz$

Explanation:

From the question we are told that

The speed of the ride $v = 6,2 m/s$

The frequency of the oboe is $f = 440Hz$

The temperature outside is $T = 27^oC$

Generally the speed of sound generated in air is mathematically evaluated as

$v_s = 331 + 0.61 T$

Substituting value

$v_s = 331 + 0.61 *27$

$v_s = 347.47 \ m/s$

The frequency of sound(generated by the musician on he park) getting to the musicians on the unicycle is mathematically evaluated as

$f_a = \frac{v_s }{v_s - v} f$

substituting values

$f_a = \frac{347.47 }{347.47 - 6.2} * 440$

$f_a = 448Hz$

Since the musician on the park is not moving the frequency of sound (from the musicians riding the unicycle )getting to him is = 440Hz

The beat frequency these musician here is mathematically evaluated as

$f_t = f_a - f$

So $f_t = 448 - 440$

$f_t = 8Hz$

3 0

3 years ago