I don’t think so because an ice cube melting needs heat and relies on temp while ooblecks transition from solid to quickly depends on force and speed
Answer:
the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.
Explanation:
When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.
Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.
The whole process must be analyzed using conservation of the moment.
p₀ = m v₀
celestines que clash case
p_f = (m + M) v
po = pf
m v₀ = (n + M) v
v = 
calculemos
v= 
v= 0.09 m/s
elastic shock case
p₀ = m v₀
p_f = m v₁ +M v₂
p₀ = p_f
m v₀ = m v₁ + m v₂
We use the radioactive decay equation for this problem which is expressed as:
An = Aoe^-kt
An is the remaining amount after time t, Ao is the initial amount and k is a constant.
First, we determine the k from the half life as follows:
An/Ao = 1/2 = e^-k(14.4)
k = 0.04814
Then, we can calculate An after 28.8 yr.
An = 1000 e^-0.04814(28.8)
An = 250 g