The image will form in the vicinity of F. Its nature will be small and inverted
Answer:
Explanation:
The forces exerted by each mass is best understood in terms of their momentum.
Momentum is a sort of compelling force or impulse. It is given as:
Momentum = mass x velocity
Let us consider the momentum of the balls;
Substance C;
Mass = 1kg
Velocity = 5m/s
Momentum of C = 1 x 5 = 5kgm/s
Substance D:
Mass = 100kg
Velocity = 5m/s
Momentum of D = 100kg x 5m/s = 500kgm/s
Body D has a higher momentum compared to Body C. This suggests that body D will exert a higher force than C when they collide.
The higher the momentum, the more the force of impact it has.
Answer:
a. A = 0.1656 m
b. % E = 1.219
Explanation:
Given
mB = 4.0 kg , mb = 50.0 g = 0.05 kg , u₁ = 150 m/s , k = 500 N / m
a.
To find the amplitude of the resulting SHM using conserver energy
ΔKe + ΔUg + ΔUs = 0
¹/₂ * m * v² - ¹/₂ * k * A² = 0
A = √ mB * vₓ² / k
vₓ = mb * u₁ / mb + mB
vₓ = 0.05 kg * 150 m / s / [0.050 + 4.0 ] kg = 1.8518
A = √ 4.0 kg * (1.852 m/s)² / (500 N / m)
A = 0.1656 m
b.
The percentage of kinetic energy
%E = Es / Ek
Es = ¹/₂ * k * A² = 500 N / m * 0.1656²m = 13.72 N*0.5
Ek = ¹/₂ * mb * v² = 0.05 kg * 150² m/s = 1125 N
% E = 13.72 / 1125 = 0.01219 *100
% E = 1.219
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