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4 years ago

How is refraction different from reflection?

1 answer:

5 0

The angle of refraction is not necessarily equal to the angle
of incidence, whereas the angle of reflection always is.

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Explain the difference between mass and weight for objects on earth and on the moon

blsea [12.9K]

Answer: Gravity causes a change in the mass of objects on earth and the moon.

Explanation:

Because of gravity, the weight of objects lessen, and decrease because of gravity. If you were to drop an object from earth from space, the object would have more mass. Hope that helps.

3 0

3 years ago

Read 2 more answers

Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it

lesya692 [45]

Answer:

$v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)$

Explanation:

As we know that the mass is revolving with constant angular speed in the circle of radius R

So we will have

$\theta = \omega t$

now the position vector at a given time is

$r = Rcos\theta \hat i + R sin\theta \hat j$

now the linear velocity is given as

$v = \frac{dr}{dt}$

$v = (-R sin\theta \hat i + R cos\theta \hat j)\frac{d\theta}{dt}$

$v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)$

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3 years ago

Juan roller skates with a constant speed of 20km/h. How long will he take to travel a distance of 70 kilometers?

VMariaS [17]

3 hours and 30 minutes.Tell Juan to get a life.

8 0

4 years ago

Anaerobic metabolism:

goblinko [34]

Explanation:

B. leads to muscle strain.

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3 years ago

Satellite A orbits a planet at a distance d from the planet’s center with a centripetal acceleration a0. A second identical sate

leva [86]

To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:

$F_g = \frac{GMm}{r^2}$

Where,

G = Gravitational constant

M = Mass of earth (in this case)

m = mass of satellite

r = radius

In the other hand we have the second's newton law:

$F = ma$

Where,

m = mass

a = acceleration

Equation both equations we have,

$ma = \frac{GMm}{r^2}$

For the problem we have that,

Satellite A:

$ma_A = \frac{GMm}{r^2}$

Satellite B:

$ma_B = \frac{GMm}{(2r)^2}$

The ratio between the two satellites would be,

$\frac{ma_A}{ma_B}= \frac{\frac{GMm}{r^2}}{\frac{GMm}{(2r)^2}}$

Solving for a_B,

$a_B = \frac{a_A}{4}$

Therefore the centripetal acceleration of $A_B$ is a quarter of $a_A$

7 0

3 years ago