The acceleration of the charge is 1.07 × 10²⁸ m/s². It is obtained as the force per unit mass of the charge.
<h3>What is Columb's law?</h3>
The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The electric force is found as;
The acceleration of the charge is found as;
Hence,the acceleration of the charge is 1.07 × 10²⁸ m/s².
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Answer:
2000 W
Explanation:
First of all, we need to find the output voltage in the transformer, by using the transformer equation:
where here we have
V1 = 200 V is the voltage in the primary coil
V2 is the voltage in the secondary coil
N1 = 250 is the number of turns in the primary coil
N2 = 500 is the number of turns in the secondary coil
Solving for V2,
Now we can find the power output, which is given by
P = VI
where
V = 400 V is the output voltage
I = 5 A is the output current
Substituting,
P = (400 V)(5 A) = 2,000 W
A: Some physical properties change, but the substance keeps its identity.
Answer:
Is your question asking for the muzzle velocity of the bullet?
Explanation:
I will assume it does
The bullet travels horizontally to the target in the same amount of time it falls 2.3 cm from vertical rest
s = ½at²
t = √(2s/g) = √(2(0.023) / 9.8) = 0.0685118...s
v = d/t = 47/0.0685118 = 686.01242...
v = 690 m/s
