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3 years ago

Earthquake information would most likely be shown on which type of map?

Physics

1 answer:

zmey [24]3 years ago

6 0

Information about Earthquakes would normally be shown on a map called "geologic hazards"

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Find the resultant of the following forces: 3.0N east, 4.0N west, and 5.0N in a direction north 60° west.

zzz [600]

Answer:

5.5 N at 50.8° north of west.

Explanation:

To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.

The three forces are:

$F_1=3.0 N$ (east)

$F_2=4.0 N$ (west)

$F_3=5.0 N$ (at 60° north of west)

Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:

$F_{1x}=3.0 N\\F_{1y}=0$

$F_{2x}=-4.0 N\\F_{2y}=0$

$F_{3x}=-(5.0)(cos 60^{\circ})=-2.5 N\\F_{3y}=(5.0)(sin 60^{\circ})=4.3 N$

Threfore, the components of the resultant force are:

$F_x=F_{1x}+F_{2x}+F_{3x}=3.0+(-4.0)+(-2.5)=-3.5 N\\F_y=F_{1y}+F_{2y}+F_{3y}=0+0+4.3=4.3 N$

Therefore, the magnitude of the resultant force is

$F=\sqrt{F_x^2+F_y^2}=\sqrt{(-3.5)^2+(4.3)^2}=5.5 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{|F_x|})=tan^{-1}(\frac{4.3}{3.5})=50.8^{\circ}$

And since the x-component is negative, it means that this angle is measured as north of west.

7 0

3 years ago

Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five second

REY [17]

Answer:

E = 75 J

Explanation:

First, we will calculate the total power consumed by the five lamps:

$Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W$

Now, the energy supply can be calculated as follows:

$E = Pt$

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

8 0

3 years ago

during the course of songraphic exam, you notice lateral splaying of echoes in the far field. what can you do to improve the ima

horrorfan [7]

Answer:

lateral splaying of echoes in the far field can be improved by Increasing the maximum number of transmit focal zones and optimize their location.

8 0

3 years ago

The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 13.1

ahrayia [7]

Answer:

The temperature is $T = 168.44 \ K$

Explanation:

From the question ewe are told that

The rate of heat transferred is $P = 13.1 \ W$

The surface area is $A = 1.55 \ m^2$

The emissivity of its surface is $e = 0.287$

Generally, the rate of heat transfer is mathematically represented as

$H = A e \sigma T^{4}$

=> $T = \sqrt[4]{\frac{P}{e* \sigma } }$

where $\sigma$ is the Boltzmann constant with value $\sigma = 5.67*10^{-8} \ W\cdot m^{-2} \cdot K^{-4}.$

substituting value

$T = \sqrt[4]{\frac{13.1}{ 0.287* 5.67 *10^{-8} } }$

$T = 168.44 \ K$

7 0

4 years ago

you check the weather and find that the winds are coming from the west at 15 milers per hour. this information describes the win

nydimaria [60]

Answer:

Velocity

Explanation:

We finds that the winds are coming from the west at 15 miles per hour. This information shows the velocity of the wind. Since, velocity is a vector quantity. It has both magnitude and direction. 15 miles per hour shows the speed of wind and west shows the direction of wind motion.

Hence, the given information describes wind velocity.

6 0

3 years ago