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IgorLugansk [536]
4 years ago
14

Find the value of each trigonometric ratio

Mathematics
1 answer:
Mila [183]4 years ago
8 0

27)\\sine=\dfrac{opposite}{hypotenuse}\\\\\text{We have:}\\opposite=40\\hypotenuse=50\\\\\sin C=\dfrac{40}{50}=\dfrac{4}{5}\\\\29)\\\\tangent=\dfrac{opposite}{adjacent}\\\text{We have:}\\opposite=18\\adjacent=24\\\\\tan C=\dfrac{18}{24}=\dfrac{18:6}{24:6}=\dfrac{3}{4}

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C.) 1600 pi cm3

When you do 10^2 you get 100 and you multiply that by the height so 16 and you get 1600.
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3 years ago
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What are some examples if irratinal numbers
Ivan
Pi aka 3.14 is a very commonly know irrational number
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In a box of 720 pens,40% of the pens are blue. how many blue pens are there in the box?
romanna [79]

Answer:

<em><u>blue</u></em><em><u> </u></em><em><u>pens</u></em><em><u>=</u></em><em><u>288</u></em>

Step-by-step explanation:

<em>blue</em><em> </em><em>pens</em><em>=</em><em>720×40%</em>

<em>blue</em><em> </em><em>pens</em><em>=</em><em>720×40/100</em>

<em>blue pens</em><u>=</u><u>288</u>

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3 years ago
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Exhibit 12-4 In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Li
snow_lady [41]

Answer:

b. multinomial population

Step-by-step explanation:

The data is categorical and non-overlapping. That is, there are multiple options(either the student is in the Liberal Arts College, Business College or Education College), and he cannot be in more than one option.

So this is an example of a multinomial population.

The correct answer is:

b. multinomial population

7 0
3 years ago
In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

45)

The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

x=3

Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

8 0
3 years ago
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