Answer:
The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.
Explanation:
Using Boyle's law

Given ,
V₁ = 14.65 L
V₂ = 7.94 L
P₁ = ?
P₂ = 5.02 atm
Using above equation as:




<u>The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.</u>
Answer:
false
Explanation:
first of all;-energy lead to an indotermic reaction.
indotermic is a reaction that absorbs energy \
*it has positive enthalpy of reaction
*Heat content of product is greater than that of reactant
*Heat is added to reactant side
example;- CO^2+2H^2+891kj --------- CH4 +2O2
Answer:
B. six protons, six neutrons, and six electrons
Explanation:
Carbon-14 and Carbon-12 are the isotopes of carbon.
Isotope:
An atom of an element that contain same atomic number but different atomic mass.
The difference in atomic mass is due to the different number of neutrons present, but the number protons and electrons are remain same.
In C-14 there are six protons and six electrons while number of neutrons are,
Mass number - number of protons = number of neutrons
14- 6 = 8
In C-12 there are six protons and six electrons while number of neutrons are,
Mass number - number of protons = number of neutrons
12- 6 = 6
Thus in C-12, there are six protons, six neutrons and six electrons present.
Answer : The oxidizing element is N and reducing element is O.
is act as an oxidizing agent as well as reducing agent.
Explanation :
An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.
Reducing agent is the agent which has ability to reduce other or lower in oxidation number.
The given reaction is :

act as an oxidizing agent.
The oxidation number of N in
is calculated as:
(+1)+(x)+3(-2) = 0
x = +5
And the oxidation number of N in
is calculated as:
(+1)+(x)+2(-2) = 0
x = +3
From the oxidation number method, we conclude that the oxidation number reduced this means
itself get reduced to
and it can act as an oxidizing agent.
act as a reducing agent.

The oxidation number of O in
is calculated as:
(+1)+(+5)+3(x) = 0
x = -2
The oxidation number of O in
is Zero (o).
Now, we conclude that the oxidation number increases this means
itself get oxidized to
and it can act as reducing agent.