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oksian1 [2.3K]
3 years ago
15

How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x

minus 1.(x + 12) = 4x – 1 zero one two infinitely many
Mathematics
3 answers:
Firlakuza [10]3 years ago
7 0

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

\dfrac{1}{2}(x+12)=4x-1

Multiply this equation by 2:

2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)

Use distributive property:

x+12=8x-2

Combine the like terms:

x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2

Thus, this equation has one solution x = 2

noname [10]3 years ago
6 0

Answer:

2

Step-by-step explanation:

Naetoosmart2 years ago
0 0

(D) Infinitely many is the actual right answer

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Answer:

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den301095 [7]

Answer:

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(x2−1)(x+1)≥0. pls help me​
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Step-by-step explanation:

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