I took the liberty of finding for the complete question.
And here I believe that the problem asks for the half life of Curium. Assuming
that the radioactive decay of Curium is of 1st order, therefore the
rate equation is in the form of:
A = Ao e^(-kt)
where,
A = amount after t years = 2755
Ao = initial amount = 3312
k = rate constant
t = number of years passed = 6
Therefore the rate constant is:
2755/3312 = e^(-6k)
-6k = ln (2755/3312)
k = 0.0307/yr
The half life, t’, can be calculated using the formula:
t’ = ln 2 / k
Substituting the value of k:
t’ = ln 2 / 0.0307
t’ = 22.586 years
or
t’ = 22.6 years
Answer:
help me first
Step-by-step explanation:
Answer:
Slope-Intercept: y = -x + 5
Point-Slope: y - 5 = -1x
Step-by-step explanation:
Slope intercept is known as y = mx + b, where m is the slope, and b is the y-intercept. To find slope, you can count or use the slope formula, and you should get -1. The y intercept is where x = 0, and in this case, b = 5.
Point slope can be altered to make slope intercept so this makes this part easier. The general formula is y - y1 = m(x - x1), where y1 and x1 are coordinate points and m is the slope. We already know slope from earlier, -1, so now we just need a coordinate point. You could use (0, 5). Now plug in the points; 0 for x1 and 5 for y1. Simplify and you're done.
Answer:
add 64 to both sides
Step-by-step explanation:
x = -26.3
