the answer is:500
step by step explanation: i don't know if i'm right by the way
Given:
A spinner marked A, B, C is spun then a 6-sided die is rolled.
To find:
The probability of getting a B and then a 6.
Solution:
We know that,
Total possible values for a spinner are 3. So, the probability of getting B, we get
Total possible values for a die are 6. So, the probability of getting 6, we get
Now, the probability of getting a B and then a 6 is
The required probability is 
.
Therefore, the correct option is D.
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
Learn more about Error here
brainly.com/question/17062640
#SPJ4
Step-by-step explanation:
60x + 3300 = 24000
60x = 24000 - 3300
60x = 20700
x = 20700 ÷ 60
x = 345
x ≤345
Depends on what you're trying to study
