Answer:
a) 116.67 MPa
b) 368.85 GPa
c) -1.0122 *10^{-4}
Explanation:
Given data:
length of bar is 1.50 m
total elongation in bar = 1.22 mm
axial load = 35.0 kN
cross section dimension = 6 by 50 mm
proportional limit = 300 MPa
a) AXIAL STRESS
Stress =force/area
b) modulus of elasticity
where E = modulus of elasticity
E = 36.8.85 GPa
c)
where is poisson's ration= 0.32
Answer:
Pressure difference (ΔP) = 63,519.75 kpa
Explanation:
Given:
ρ = 1,000 kg/m³
Height of cylindrical container used (h) = 7m / 2 = 3.5m
Specific gravity (sg) = 0.85
Find:
Pressure difference (ΔP).
Computation:
⇒ Pressure difference (ΔP) = h g [ ρ(sg) + ρ] ∵ [ g = 9.81]
⇒ Pressure difference (ΔP) = (3.5)(9.81) [ 1,000(0.85) + 1,000]
⇒ Pressure difference (ΔP) = 34.335 [8,50 + 1,000]
⇒ Pressure difference (ΔP) = 34.335 [1,850]
⇒ Pressure difference (ΔP) = 63,519.75 kpa