Let distance form the pole = x and height of the hill = y ft
now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x
from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x
x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40
x = 40 / (tan18 + tan 14) = 69.66 feet Answer
We are given with the rate of change of the base, db/dt equal to 1 ft/ sec and the rate of change of the height of the triangle, dh/dt equal to 2 ft/sec. b is 10 ft and h is 70 ft. Area of triangle is equal to A= 0.5 bh The rate of change of the area is equal to dA/dt = 0.5 b dh/dt + 0.5 h db/dt. Substituting, dA= 0.5*10*2 + 0.5*70 * 1 equal to 45 ft2 / sec.
Answer is choice B: the circumference of a circle is the same as perimeter and is defined by πd (or pi times diameter) We can cut this in half because we are working with a semicircle: so we have 6π which approximates to the value in answer
when using 3.14 for pi
Woops: forgot to add the diameter of 12 so we would have 30.84
This is how to solve this
The "x-intercept" occurs when y=0, because it is at this point that the equation touches the x axis. So if you plug in y=0 into the equation you can solve for the x coordinate.
4x-2(0)-8=0
4x-8=0
4x=8
x=2
So the x-intercept is the point (2,0)
