how much of each ingredient would you make an identical recipe that serves 24 people? explain your answer

1 answer:

3 0

Ok, so increasing a recipe originally for 16 to 24, you need to figure out how many times larger you need the recipe, so divide 24 by 16, and you get 1.5 (one and a half times larger)
You then just need to take each ingredient amount and multiply it by 1.5
2 cans chopped clams x 1.5 = 3 cans
4 cups broth x 1.5 = 6 cups
6 cups milk x 1.5 = 9 cups
4 cups cubed potatoes x 1.5 = 6 cups
Does this make sense?

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nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

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Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

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2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

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3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$