Answer:
Explanation:
Using the formula for refraction at curved surface
For refraction at first surface
μ₂ /v -μ₁ /u = ( μ₂ - μ₁ )/R
1.5/v -1/-45 =.5/14
v = 111 cm
For refraction at opposite surface ,
u ( object distance ) = 111 - 28 =83 cm
It will act as virtual object for surface 2 so it will be positive in sign
again using the above equation for 2 nd surface we have
1/v - 1.5/83.17 = -.5-=/-14 = 1/28
v = 18.62 cm from second face.
yes, virtual image will be formed.
The input force will increase too because the more the ramp is increasing the more force is being put on the object going down the ramp... hope this helps ^-^
Answer:
Part a)

Part b)

Part c)

Part d)

Part e)

Explanation:
Part a)
initial vertical position = 1.02 m
maximum height = 1.80 m





time taken by it to reach this height



Now when it again touch the ground then its speed is given as



time taken by it to reach this height





Part b)
Horizontal velocity



Part c)
vertical velocity is the intial y direction velocity

Part d)
Take off angle is given as


Part e)
initial vertical position = 1.20 m
maximum height = 2.50 m





time taken by it to reach this height



Now when it again touch the ground then its speed is given as



time taken by it to reach this height





Is there any numbers to your question?
Keep in mind, the energy is conserved in a pendulum.
Here’s more information:
https://blogs.bu.edu/ggarber/interlace/pendulum/energy-in-a-pendulum/
Answer:
C
Explanation:
An object in motion will stay in motion unless acted on by a net positive or negative force.
For answer A. If the object were to be in an orbit, it would inevitably accelerate due to it being acted on by the gravitational force from the object it is orbiting. At different points in the orbit, the object will move at different speeds and continuously transfer between kinetic and potential energy.
For answer B. The object would would not stop their motion. In order for the object to lose energy, it would have to transfer it through friction or through its interaction with a gravitational field.
For answer D. No energy is "required" to maintain constant motion unless the object is willingly fighting against a resistive force like friction or a graviational well.