Answer:
I =
(K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr
Now integrating we get
I = 
I = (K+5) 2π
I = (K+5) 2π 
I =
(K+5)
All of that fluff at the beginning is interesting, but completely irrelevant
to the question. The question is just asking for the mass of an object
that weighs 3.6N on Earth.
Weight = (mass) x (acceleration of gravity)
3.6N = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s : Mass = 3.6N / 9.8 m/s² = <em>0.367 kilogram</em> (rounded)
Answer:
40 cm
Explanation:
We are given that
Load=800 N
Effort=200 N
Load distance=10 cm
We have to find the effort distance.
We know that

Using the formula

Effort distance=
Effort distance=
Effort distance=40 cm
Hence, the effort distance will be 40 cm.