Using the general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
(105*220)/275 = (P₂*95)/310
(105*220)*310/275 = P₂*95
(105*220*310)/(275*95) = P₂
274.11 = P₂
P₂ = 274.11 kPa
New Pressure = 274.11 kPa
Answer : The molar volume of the gas will be, 44.82 L
Solution :
Using ideal gas equation,

where,
n = number of moles of gas = 1 mole
P = pressure of the gas = 0.5 atm
T = temperature of the gas = 273 K
R = gas constant = 0.0821 Latm/moleK
V = volume of the gas.
Now put all the given values in the above equation, we get the molar volume of the gas.


Therefore, the molar volume of the gas will be, 44.82 L
Answer : The
must be administered.
Solution :
As we are given that a vial containing radioactive selenium-75 has an activity of
.
As, 3.0 mCi radioactive selenium-75 present in 1 ml
So, 2.6 mCi radioactive selenium-75 present in 
Conversion :

Therefore, the
must be administered.
Answer:
Number of moles of Al = 0.02 mol
Number of moles of CuCl₂ = 0.02 mol
Explanation:
Given data:
Mass of CuCl₂ = 2.50 g
Moles of CuCl₂ = ?
Solution:
Formula:
Number of moles = mass / molar mass
Molar mass of CuCl₂ = 63.546 + 35.5 ×2
Molar mass of CuCl₂ = 134.546 g/mol
Now we will put the values in formula:
Number of moles = 2.50 g / 134.546 g/mol
Number of moles = 0.02 mol
Given data:
Mass of Al = 0.50 g
Moles of Al = ?
Solution:
Formula:
Number of moles = mass / molar mass
Molar mass of Al = 27 g/mol
Now we will put the values in formula:
Number of moles = 0.50 g / 27 g/mol
Number of moles = 0.02 mol
Not totally sure, but I think it’s A.