Question

#1. Boyle's Law. A gas with a volume of 4.0 L at a pressure of 205 kPa is allowed to expand to a volume of 12.0 L.

Answer 1

The final pressure in the container if the temperature remains constant is 68.3 kPa.

Given the following data;

• Initial volume, V1 = 4.0 liters

• Initial pressure, P1 = 205 kPa

• Final volume, V2 = 12.0 Liters

To find the final pressure in the container if the temperature remains constant, we would use Boyle's Law:

Mathematically, Boyle's law is given by the formula;

$P_1V_1 = P_2V_2$

Where;

• P1 is the original (initial) pressure.

• P2 is the final pressure.

• V1 is the original (initial) volume.

• V2 is the final volume.

Substituting the values into the formula, we have;

$205$ × $4 =$ $12P_2$

$820 = 12P_2\\\\P_2 = \frac{820}{12}$

Final pressure, P2 = 68.3 kPa

Therefore, the final pressure in the container if the temperature remains constant is 68.3 kPa.

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