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den301095 [7]
4 years ago
7

What is the vertical movement of the surface of a body of water called?

Chemistry
2 answers:
Elodia [21]4 years ago
5 0

Answering the question, the vertical movement of the surface of a water body is called Tide.

<h3>Further Explanation</h3>

Tides are one the major movement of a water body. Other notable movements are:

  • Waves
  • Ocean currents

Tides are usually long-period waves which move through the oceans in accordance to forces put out by the sun and moon.

Tides are known to originate in the oceans and further move along the coastlines where they fluctuate in rising and falling patterns, across the sea surface.

The rise and fall of the Tides are particularly described as high and low tide respectively. High tides occur when the highest part of a wave reached a particular place. Low tide occurs when the wave it at its lowest part at a particular place.

Notably, a horizontal movement of water which is in line with the rise and fall of the tide is called tidal current.

However, there are three types of Tides  

  • Diurnal Tide
  • Semi-diurnal Tide
  • Mixed Tide

Diurnal Tide

This particular type of Tide has just one high tide and a corresponding low tide per day.

Semi-Diurnal Tide

Semi-Diurnal Tides have two occurrences of both high and low tides in each day.

Mixed Tide

This type of tide also has two occurrences of both high and low tides in each day, but at unequal levels in terms of height.

LEARN MORE:

  • Tide brainly.com/question/10317126

KEYWORDS:

  • Tide
  • Waves
  • Oceans
  • Diurnal
  • Semi-Diurnal
  • Mixed
qaws [65]4 years ago
4 0
The vertical movement of a surface of a body of water is called tide. Tide is the alternate rising and falling of a body of water at a particular time and in a particular place as a result of the combined effects of the gravitational pull exerted by the moon and the star.
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tatiyna

Answer:

8.0 g

Explanation:

To convert moles to grams, you need to use the molar mass.  The molar mass of sulfur is 32.06.  The molar mass is the atomic mass of the atom.

(0.25 mol) × (32.06 g/mol) = 8.015 g

Round for significant figures.

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A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
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Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

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it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

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Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

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