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3 years ago

What is the overall order of reaction for this rate law: Rate = k ? zero first second third

2 answers:

3 0

The overall order of a reaction is directly related to the reaction mechanism of the reaction. The reaction mechanism is defined by the reaction rate equation. In this case, we are given by the equation, Rate=k. The order of this reaction is zero since the rate is not dependent on the concentration of reactants or products.

ryzh [129]3 years ago

3 0

Answer: The order of the reaction for the given rate law is zero.

Explanation:

Order of the reaction is defined as the sum of the exponents or powers to which the molar concentration in the rate law equation are raised to express the observed rate of the reaction. For a given general equation:

$aA\rightarrow cC+dD$

Rate law is given as: $Rate=k[A]^a$

Order of the reaction will be = a

For the given rate law: $Rate=k[A]^0$

In the rate law, anything raised to power 0 is 1.

Order of the give rate law = 0

And, hence, the order of the reaction will be zero.

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RoseWind [281]

It is a radio wave

Explanation:

The energy of an electromagnetic waves is related to its frequency by the equation:

$E=hf$

where

h is the Planck constant

f is the frequency of the wave

We notice that the energy of an electromagnetic wave is proportional to its frequency. This means that waves with higher frequencies, such as gamma rays, x-rays, are more energetic, while waves with lower frequencies, such as microwave and radio waves, are the less energetic.

In this case, we want to find the frequency of a wave with energy

E = 0.000001 eV

Converting into Joules,

$E=1\cdot 10^{-6} eV \cdot 1.6\cdot 10^{-19} J/eV=1.6\cdot 10^{-25} J$

Solving for the frequency,

$f=\frac{E}{h}=\frac{1.6\cdot 10^{-25}}{6.63\cdot 10^{-34}}=2.4\cdot 10^8 Hz = 240 MHz$

Which falls in the range of frequency of radio waves.

Learn more about electromagnetic waves:

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#LearnwithBrainly

4 0

3 years ago

How many electrons are in an electrically neutral atom of boron? A-3 B-5 C-6 D-8

djverab [1.8K]

The answer would be D-8

4 0

3 years ago

Read 2 more answers

For the reaction where Δn=−1Δn=−1 , what happens after in increase in volume? ????KQ>K so the reaction shifts toward reactant

Alex787 [66]

Answer:

Explanation:

In general, an increase in pressure (decrease in volume) favors the net reaction that decreases the total number of moles of gases, and a decrease in pressure (increase in volume) favors the net reaction that increases the total number of moles of gases.

Δn= b - a

Δn= moles of gaseous products - moles of gaseous reactants

Therefore, <u>after the increase in volume</u>:

If Δn= −1 ⇒ there are more moles of gaseous reactants than gaseous products. The equilibrium will be shifted towards the products, that is, from left to right, and K>Q.
If Δn= 0 ⇒ there is the same amount of gaseous moles, both in products and reactants. The system is at equilibrium and K=Q.
Δn= +1 ⇒ there are more moles of gaseous products than gaseous reactants. The equilibrium will be shifted towards the reactants, that is, from right to left, and K<Q.