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3 years ago

What is the overall order of reaction for this rate law: Rate = k ? zero first second third

2 answers:

3 0

The overall order of a reaction is directly related to the reaction mechanism of the reaction. The reaction mechanism is defined by the reaction rate equation. In this case, we are given by the equation, Rate=k. The order of this reaction is zero since the rate is not dependent on the concentration of reactants or products.

ryzh [129]3 years ago

3 0

Answer: The order of the reaction for the given rate law is zero.

Explanation:

Order of the reaction is defined as the sum of the exponents or powers to which the molar concentration in the rate law equation are raised to express the observed rate of the reaction. For a given general equation:

$aA\rightarrow cC+dD$

Rate law is given as: $Rate=k[A]^a$

Order of the reaction will be = a

For the given rate law: $Rate=k[A]^0$

In the rate law, anything raised to power 0 is 1.

Order of the give rate law = 0

And, hence, the order of the reaction will be zero.

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Explanation:

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3 years ago

How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide

Marat540 [252]

Answer:

$\boxed{\text{2.00 mol}}$

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r: 58.32

Mg(OH)₂ + … ⟶ … + 2HOH

m/g: 58.3

(a) Moles of Mg(OH)₂

$\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}$

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

$\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}$

The reaction will form $\boxed{\textbf{2.00 mol}}$ of water.

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3 years ago

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Komok [63]

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3 years ago

How many grams of h2 are needed to react with 48 grams of o2, given the reaction: 2 h2 (g) + o2 (g) --> 2 h2o (l)?

photoshop1234 [79]

1.Calculate the number of mole of O2: 48/32=1.5 mol
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1 year ago