For the answer to the question above,
1∙5µm² = ? m²
1m * 1m = 1m² But 1m = 1,000,000µm = 1x 10^6µm 1x10^6µm * 1x10^6µm = 1m² 1x 10^12µm² = 1m² (Now, try dividing both sides by 1x10^12). 1x10^12µm² /(1x10^12) = 1m² /(1x10^12) 1µm² = 0∙000 000 000 001 m² (multiply both sides by by 1∙5). 1∙5µm² = 0∙000 000 000 0015 m²
1∙5µm² = 1∙5x 10^-12 m²
I hope this helps
Answer:
If mass remains the same while the volume of a substance changes, the density of the substance will also change.
Answer:
29.75 Kg of NH₃
Solution:
In order to calculate the theoretical yield, first we will identify the limiting reactant.
According to equation,
6 g (3 moles) H₂ requires = 28 g (1 mole) N₂
So,
5250 g H₂ will require = X g of N₂
Solving for X,
X = (5250 g × 28 g) ÷ 6 g
X = 25433 g of N₂
Hence, it is found that H₂ is the limiting reactant because N₂ is provided in excess (32700 g). Therefore,
As,
6 g (3 mole) H₂ produced = 34 g ( 2 moles) of NH₃
So,
5250 g H₂ will produce = X g of NH₃
Solving for X,
X = (5250 g × 34 g) ÷ 6 g
X = 29750 g of NH₃
Or,
X = 29.75 Kg of NH₃
Answer:
H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).
Explanation:
