1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
schepotkina [342]
3 years ago
9

Which chemical equation follows the law of conservation of mass​

Chemistry
2 answers:
Neko [114]3 years ago
4 0

Answer:

the law of conversation of mass States that mass is an isolated system is neither created or destroyed by chemical reactions or physical transformations. according to the law of conversation of mass the mass of the product in a chemical reaction must equal to the mass of reactants

hope It helped you

seraphim [82]3 years ago
3 0
The answer is A, because there is the same amount of atoms on each side.
You might be interested in
Which substance will have the higher melting point,ethanol or ethane?explain
attashe74 [19]

Since hydrogen bonding is a stronger intermolecular force than van der Waals forces, more energy is required to separate the molecules of ethanol than the molecules of ethane. Thus ethanol has a higher melting point than ethane.

6 0
3 years ago
How many moles of C3H8 will be produced from 75 moles of CO2?C3H8 + 5 O2 → 3 CO2 + 4 H2O
levacccp [35]

25 moles of C3H8 will be produced from 75 moles of CO2.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

                             C_3H_8 + 5 O_2 = > 3 CO_2 + 4 H_2O

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:3, so we can perform the following expression:

                           

                            C3H8                CO2

                                      \frac{1mol}{xmol} =\frac{3mol}{75mol}

                                         x = 25mol

So, 25 moles of C3H8 will be produced from 75 moles of CO2.

Learn, more about mole calculation in: brainly.com/question/2845237

8 0
2 years ago
Three sections of the periodic table are labeled A, B, and C in the image. Which of the following statements is MOST LIKELY true
Marizza181 [45]
I think the answer is A
8 0
3 years ago
Read 2 more answers
Paper burns to ash is a chemical change.<br>​
dimaraw [331]

Answer:

Yes, it is

Explanation:

Hope this helps!

3 0
3 years ago
Read 2 more answers
H2 + CaCl2 --&gt; 2HCl + Ca How many grams of HCl are made when 2.93 g of<br><br> Ca are made?
Sholpan [36]

Answer:

H2 + CaCl2 -> 2HCl + Ca

How many grams of HCl are made when 2.93 g of

Ca are made?

Explanation:

From the given balanced chemical equation, it is clear that:

2mol. of HCl and 1mol. of Ca are produced.

2mol. of HCl weighs --- 73.0g

1mol. of Ca weighs --- 40.0g

Hence,

73.0g of HCl and 40.0g of Ca are produced.

When 2.93g of Ca is produced then, how many grams of HCl will be produced?

=> 2.93g Ca * \frac{73.0g HCl}{40.0g Ca} \\=5.35g HCl

Hence, 5.35g of HCl is formed.

4 0
3 years ago
Other questions:
  • Which of these is a property of acids?
    15·2 answers
  • Help Please earth science
    9·1 answer
  • ____is not a resource that can be used to help meet our energy needs
    8·1 answer
  • Draw the mechanism for the reaction of an alkyl halide with sodium azide
    6·1 answer
  • Reactants → products
    9·1 answer
  • Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide.
    15·1 answer
  • What is the volume of an object with a density of 2.6 g/cm³ and a mass of 30.5g?
    14·1 answer
  • Check all the examples below that represent a physical property of matter​
    12·2 answers
  • Answer the following question for this equation: 2H2 + O2 → 2H2O
    7·1 answer
  • purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!