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xenn [34]
2 years ago
15

3. A 4.00 gram sample of solid gold was heated from 274K to 314K. How much energy was involved?

Chemistry
1 answer:
MrMuchimi2 years ago
3 0
Q = mcΔT = (4.00 g)(0.129 J/g•°C)(40.85 °C - 0.85 °C)
Q = 20.6 J of energy was involved (more specifically, 20.6 J of heat energy was absorbed from the surroundings by the sample of solid gold).
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Calculate the grams of ethane present in a sample containing 0.4271 moles if the molar mass of ethane is 30.067 g/mol.
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The grams of ethane present in a sample containing 0.4271 mole is 12.84 g

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mass of ethane. Details below

<h3>How to determine the mass of ethane</h3>

The following data were obtained from the question:

  • Mole of ethane = 0.4271 mole
  • Molar mass of ethane = 30.067 g/mol
  • Mass of ethane =?

The mass of ethane present in the sample can be obtained as follow:

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of ethane = 0.4271 × 30.067

Mass of ethane = 12.84 g

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