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xenn [34]
3 years ago
15

3. A 4.00 gram sample of solid gold was heated from 274K to 314K. How much energy was involved?

Chemistry
1 answer:
MrMuchimi3 years ago
3 0
Q = mcΔT = (4.00 g)(0.129 J/g•°C)(40.85 °C - 0.85 °C)
Q = 20.6 J of energy was involved (more specifically, 20.6 J of heat energy was absorbed from the surroundings by the sample of solid gold).
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19. This type of bond involves the bonding of two ions of opposite charges
hammer [34]

Answer:

Covalent bond is a type of bond involves the bonding of two ions of opposite charges.

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7 0
3 years ago
think about putting a glass of water on the counter, in the freezer, and on a hot stove how does the temperature of the water af
Shtirlitz [24]

The kinetic energy and the physical state of water depend strongly on the temperature;

  • Firstly, The kinetic energy of water on a hot stove is higher than that on the counter in the freezer; that the kinetic energy is directly proportional to the temperature according to the relation: K = \frac{3RT}{2NA} ; where R is the universal gas constant, T is the temperature and NA is Avogadro number.

As the temperature increases, the speed of colliding molecules increases and the kinetic energy increases.

  • Secondly, The physical state of water depends on the temperature; water has three states (gas, liquid and solid) depends on the temperature.
  • If a glass of water is putt on the counter in the freezer, it will be converted to the solid state (ice).
  • And, as if it is putt on a hot stove, it will be vapor (gaseous state).

3 0
3 years ago
Consider an insulated container in which water (2.58 g) solidifies at 0 oC and 1 atm on the surface of a 55 g aluminum block. As
yarga [219]

Answer:

17.41°C is the change in temperature of the aluminum block.

Explanation:

Latent heat of fusion water = 334 J/g

Heat required to freeze 1 gram of water = -334 J

Heat required to freeze 2.58 grams of water = Q

Q=2.58 g\times (-334 J/g)=-861.72 J

Heat lost by water will be equal to heat gained by the aluminum block

Q'=-Q

Q'= -(-861.72 J)=861.72 J

Formula used to calculate heat absorbed by substance:

Q=mc\Delta T

Where:

Q = heat absorbed by substance

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Mass of aluminum block= m= 55 g

Heat capacity of aluminum = c = 0.9 J/g°C

Change in temperature of the aluminum block= ΔT = ?

Heat absorbed by the aluminum = Q'

861.72 J=55 g\times 0.9 J/g^oC\times \Delta T

\Delta T=17.41 ^oC

17.41°C is the change in temperature of the aluminum block.

8 0
4 years ago
Beta decay can be described by the emission of an _______
olchik [2.2K]

That would be the emission of an electron.

8 0
3 years ago
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Ivenika [448]

Answer:

C

Explanation:

The train has significantly more momentum by the car, hence there is little change in the train's momentum after collision..

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6 0
3 years ago
Read 2 more answers
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