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anygoal [31]
3 years ago
13

Which one of the following statements is true?A. Some real gases have lower pressures than that calculated for the ideal gas bec

ause of attraction between molecules.B. For a real gas, PV is always less than nRT.C. Some real gases have lower pressures than that calculated for the ideal gas because of the finite volume occupied by the molecules.D. For a real gas, PV is always greater than nRT.E. Gases are likely to be more real and less ideal at high temperatures.
Chemistry
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

A. Some real gases have lower pressures than that calculated for the ideal gas because of attraction between molecules.

Explanation:

At room temperature and moderately low pressures ideal gases among other assumptions:

I. Do not attract or repel each other.

II. Have negligible volume relative to the volume of the containing vessel.

Thus the ideal gas equation:

PV = nRT

Where P = gas pressure = gas molecules' collision with the walls of the containing vessel.

V = volume occupied by the gas sample.

T = Kelvin temperature of the gas

n = number of mole of the gas present.

R = proportionality constant called the molar gas constant = 0.0821 L. atm/K.mol.

However, at low temperatures and high pressures, gases exhibit real behaviors and the

I. attractive forces between the gas molecules may not be negligible.

II. volume of the gas molecules may not be negligible relative to the volume of the container.

At low temperatures, the average kinetic energy of the gas molecules decreases which prevents the molecules breaking free from their molecular attraction.

At high pressures, the density of the gas increases and the molecules come closer to one another. This increases the intermolecular forces between the gas molecules, increases the number of molecules found per unit volume and lowers their speed moving towards the containing wall thus lowering the pressure the gas would exert than if it were in an ideal behavior.

van der Waals corrected the actual pressure and volume of real gases as follows:

( P + an^2/V^2 ) ( V – nb ) = nRT

Where n^2/V^2 = number of molecules per unit volume.

P = observed pressure.

( V – nb ) = effective volume of the gas.

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ANEK [815]

Answer: 1.0 M molecular sucrose (C₁₂H₂₂O₁₁).


Explanation:


1) The depression of the freezing point of a solvent when you add a solute is a colligative property.


2) Colligative properties are those physical properties of solutions that depends on the number of solute particles dissolved into the solution.


3) The relation between the number of solute particles and the depresson of the freezing point is proportional: the greater the number of solute particles the greater the freezing point depression.


4) You need to find the solution with the highest freezing point, this is the solution in which the freezing point decreased the least.


5) Then, that is the solution with least number of solute particles.


6) Since all the given solutions have the same molarity (1.0 M), you only have to deal with the possible ionization of the different solutes.


7) NaCl, CaBr₂, AlBr₃, and KCl are ionic compounds, so each unit of them will ionize into two, three, four, and two ions, respectively, while sucrose, being a covalent compound does not dissociate.


Then, 1.0 M solution of sucrose will have less solute particles than the others, and will exhitibit the lowest freezing point depression, meaning that it will have the highest freezing point of the given solutions.



5 0
3 years ago
Read 2 more answers
Which formula is an empirical formula?
poizon [28]
<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. NH_{3}

<h2>Why?</h2>

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

MolecularFormula=n(EmpiricalFormula)

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. N_{2}O_{4}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

N_{2}O_{4}=2(NO_{2})

B. NH_{3}

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. C_{3}H_{6}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

C_{3}H_{6}=3(CH_{2})

D. P_{4}O_{10}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

P_{4}O_{10}=2(P_{2}O_{5})

Hence, the empirical formula is the option B. NH_{3}

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