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Nataliya [291]
3 years ago
15

What % of original U238 remains after three half lives? 1-50 2-25 3-12.5 4-6.25

Chemistry
1 answer:
Grace [21]3 years ago
7 0

Answer:

12.5

Explanation:

After three half-lives, one eighth (1/2 x 1/2 x 1/2) of the uranium-238 will remain. One-eighth equals 12.5%

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The walls in your home have 25mm of expanded polystyrene (R-value 3.96) and 25mm of rigid urethane foam (R-value 7.50). What is
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Answer:

3.6 per inch

EPS insulation features an average r-value of 3.6 per inch.

In addition to providing energy efficiency, EPS without film facers has a perm rating of up to 5.0.

Explanation:

hope this helps

7 0
3 years ago
What process takes place before an article is published in a scientific journal/
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Before an article is published in a scientific journal or in any "peer-reviewed" journal the article is reviewed thoroughly by scholars from the journal as well as peers or scholars of the articles author from the same field. This process occurs to provide credibility to the ideas being published and so that readers and other scholars can rely on the validity of the material being published. 
7 0
3 years ago
Does anyone know Coulomb’s law??
Ierofanga [76]

Answer:

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3 0
3 years ago
How many particles are there in 5.0 moles​
grigory [225]

Answer:

3.01 × 10^24 particles

Explanation:

According to Avagadro, in one mole of a substance, there are 6.02 × 10^23 atoms or particles.

Using the formula: N = n × NA

Where;

N= number of particles or atoms

n = number of moles

NA = Avagadro's constant or number

This means that for 5 moles of a substance, there will be:

5 × 6.02 × 10^23

= 30.1 × 10^23

= 3.01 × 10^24 particles

8 0
3 years ago
What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol
ad-work [718]

Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 63 g * 1 mol/(58.44 g)

moles of NaCl = 1.078 moles

Finally we can find the molarity of the solution

molarity = moles of NaCl/(volume of solution)

molarity = 1.078 moles/(0.65 L)

molarity = 1.66 M

Answer: the molarity of the solution is 1.66 M.

7 0
11 months ago
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