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Nataliya [291]
3 years ago
15

What % of original U238 remains after three half lives? 1-50 2-25 3-12.5 4-6.25

Chemistry
1 answer:
Grace [21]3 years ago
7 0

Answer:

12.5

Explanation:

After three half-lives, one eighth (1/2 x 1/2 x 1/2) of the uranium-238 will remain. One-eighth equals 12.5%

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How are chemical bonds important in metabolism?
mixas84 [53]
Chemical bonds are broken to supply us with energy. Without bonds, and our ability to break them, the food we eat would not supply us with energy.
8 0
3 years ago
Using the same sample of gas (P1 = 565 torr , T1 = 27 ∘C ), we wish to change the pressure to 5650 torr with no accompanying cha
Stels [109]

Answer:

2726.85 °C

Explanation:

Given data:

Initial pressure = 565 torr

Initial temperature = 27°C

Final temperature = ?

Final pressure = 5650 torr

Solution:

Initial temperature = 27°C (27+273 = 300 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

T₂  = P₂T₁ /P₁

T₂  = 5650 torr × 300 K / 565 torr

T₂  = 1695000 torr. K /565 torr

T₂ = 3000 K

Kelvin to degree Celsius:

3000 K - 273.15 = 2726.85 °C

4 0
2 years ago
A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 ml of water, raising the water leve
jeka94

Mass of metal piece is 611 g and volume of graduated cylinder is 25.1 mL. When metal piece is placed in the graduated cylinder water level increases to 56.7 mL. The increase in volume is due to volume of metal piece that gets added to the volume of water.

Thus, volume of metal piece can be calculated by subtracting initial volume from the final one.

V_{metal}=V_{final}-V_{initial}=(56.7-25.1)mL=31.6 mL

Thus, volume of metal piece will be 31.6 mL. The mass of metal piece is given 611 g, density of metal can be calculated as follows:

d=\frac{m}{V}=\frac{611 g}{31.6 mL}=19.33 g/mL

Therefore, density of metal is 19.33 g/mL.

3 0
3 years ago
A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

6 0
3 years ago
Why is studying light and electrons important for chemistry and understanding the universe?
Brut [27]

Explanation :

The study of light and electrons are important for chemistry & universe.

   As we know, everything is made up of particles even light & universe also. The particles are made of atoms and that atoms are made up of electrons, protons & neutrons.

   An electron is one of the most important type of subatomic particles. Electrons combine with the proton to form atom. These electrons, protons & neutrons play a vital role in chemistry and universe.

   The importance of an electron is that when two atoms react with each other or approach each other, their outermost shells come into contact first and these outermost shells electrons are involved in the chemical reaction.

    Also important for chemical reactions, creating bonds, for electricity and the understanding of electrons has allowed for the better understanding of some forces which are in our universe such as electromagnetic force.

    We know that the light is act as particle nature and it is a part of universe. As we know that chemists are only responsible for the chemical's study. Chemists cannot study the whole universe that is why they study light and the light is important because nothing would be able to survive.

    The studying of light is important for the photoelectric effect, absorption, bio-molecules synthesis, vitamin D synthesis, vision, colors, drying & evaporation, sterilization, solar energy, spectroscopy, signal system and also for electron excitation.

7 0
3 years ago
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