3 years ago

What % of original U238 remains after three half lives? 1-50 2-25 3-12.5 4-6.25

Chemistry

1 answer:

Grace [21]3 years ago

7 0

Answer:

12.5

Explanation:

After three half-lives, one eighth (1/2 x 1/2 x 1/2) of the uranium-238 will remain. One-eighth equals 12.5%

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muminat

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3 years ago

The equilibrium constant, Kc, for the reaction N2O4(g)⇌2NO2(g) is 5.0×10−3. If the equilibrium mixture contains [NO2] = 0.050 M

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Answer:

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Explanation:

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4 years ago

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AleksandrR [38]

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