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3 years ago

Which formula is an empirical formula?

Chemistry

2 answers:

marta [7]3 years ago

7 0

the answer is B......

poizon [28]3 years ago

6 0

<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. $NH_{3}$

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

$MolecularFormula=n(EmpiricalFormula)$

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. $N_{2}O_{4}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$N_{2}O_{4}=2(NO_{2})$

B. $NH_{3}$

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. $C_{3}H_{6}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$C_{3}H_{6}=3(CH_{2})$

D. $P_{4}O_{10}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$P_{4}O_{10}=2(P_{2}O_{5})$

Hence, the empirical formula is the option B. $NH_{3}$

Have a nice day!

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1 year ago

Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip

avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

q = $600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}$

= 0.0378 $m^{3}/s
$

Diameter = $8 in \times \frac{0.0254 m}{1 in}$

= 0.2032 m

Relation between area and diameter is as follows.

A = $\frac{\pi}{4} \times D^{2}$

= $\frac{3.14}{4} \times (0.2032 m)^{2}$

= 0.785 x 0.2032 x 0.2032

= 0.0324 $m^{2}$

Also, q = A × V

or, V = $\frac{q}{A}$

= $\frac{0.0378 m^{3}/s}{0.0324 m^{2}}$

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As, viscosity of water = 1 cP = $10^{-3}$ Pa-s

Density of water = 1000 $kg/m^{3}$

Therefore, we will calculate Reynolds number as follows.

Reynolds number = $\frac{D \times V \times density}{viscosity}$

= $\frac{0.2032 m \times 1.166 m/s \times 1000}{10^{-3}}$

= 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

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2 years ago

Read 2 more answers

Identify the following reaction as oxidation and reduction F2(g)+2e-/2F-(aq)

sertanlavr [38]

Answer:

Reduction

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

In given reaction fluorine gas gain two electron and form fluoride ions.

F₂(g) + 2e⁻ → 2F⁻(aq)

The given reaction is reduction because oxidation state is decreased from zero to -1.

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