If function g has the factors (x - 7) and (x + 6), what are the zeros of function g?

Mathematics

2 answers:

vagabundo [1.1K]1 year ago

8 0

The zeroes of the function will be equal to ( 7, -6 ).

<h3>What is a quadratic equation?</h3>

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given function:-

( x- 7 ) ( x+ 6 )

As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.

( x- 7 ) = 0

x = 7

( x+ 6 ) = 0

x = -6

Therefore zeroes of the function will be equal to ( 7, -6 ).

To know more about quadratic equations follow

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vaieri [72.5K]1 year ago

7 0

<h2>Function Equations</h2>

When a given function is written with factors in the form of ( x - r ), then <em>r</em> is a zero of the function.

<h2>Solving the Question</h2>

We're given:

Function <em>g</em> has factors (x-7) and (x+6)

Therefore, the zeros of the function are 7 and -6.

<h2>Answer</h2>

-6, 7

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5. To get to the library from his house, Robert biked 6 kilometers due east and then

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Answer:

24 kilometers.

Step-by-step explanation:

The shortest path between two points is a straight segment that connects the two points.

Refer to the diagram attached. The 6-km segment and the 8-km segment are normal to each other. Together with the segment that joins the library and the house, the three segments now form a right triangle.

The two shorter segments are the two legs, and
The longer segment that joins the library and the house is the hypotenuse.

The length of the hypotenuse can be found with the Pythagorean Theorem.

$\begin{aligned}\text{Hypotenuse} &= \sqrt{(\text{Leg 1})^{2} + (\text{Leg 2})^{2}}\\&= \sqrt{6^{2} + 8^{2}}\\&= \sqrt{36 + 64} \\&= \sqrt{100}\\&= \rm 10\;km\end{aligned}$ .