Question

A particular brand of gasoline has a density of 0.737 g/mLg/mL at 25 ∘C∘C. How many grams of this gasoline would fill a 14.9 galgal tank ( 1US gal=3.78L1US gal=3.78L )?

Answer 1

Answer:

The answer to your question is Mass = 41230.7 g  or 41.23 kg    

Explanation:

Data

density = 0.737 g/ml

mass = ?

volume = 14.9 gal

1 gal = 3.78 l

Process

1.- Convert gallons to liters

                                   1 gal ---------------- 3.78 l

                                  14.8 gal -------------  x

                                    x = 55.94 l

2.- Convert liters to milliliters

                                  1 l -------------------  1000 ml

                              55.94 l ---------------   x

                                   x = (55.94 x 1000) / 1

                                   x = 55944 ml

3.- Calculate the mass

Formula

density = $\frac{mass}{volume}$

Solve for mass

Mass = density x volume

Substitution

Mass = 0.737 x 55944

Simplification and result

Mass = 41230.7 g  or  41.23 kg