Answer:
2.5m/s^2
Explanation:
Step one:
given
distance = 20meters
time = 2 seconds
initial velocity u= 0m/s
let us solve for the final velocity
velocity = distance/time
velocity= 20/2
velocity= 10m/s

divide both sides by 40

Given: Mass m = 60 Kg
Weight W = 96 N
Required: Acceleration due to gravity, g = ?
Formula: W = mg
g = W/g
g = 96 Kg.m/s²/60 Kg (note: this is the derive unit for Newton "N")
g = 1.6 m/s²
I attached the full question.
We need to calculate the enthalpy change first:

Keep in mind this is the energy per mole, we need energy per atom:

We can see that this reaction needs the energy to get started (enthalpy change is positive).
The energy of a photon is given with this formula:

We need this photon to have the same energy (or higher) as our enthalpy change:

This wavelenght is clasified as near infrared.
Answer:


Explanation:
From the question we are told that
Distance of eyes from the top of hat 
Distance of eyes from buckle 
Generally position of mirror relative eyes x is mathematically given as



Generally the height of the mirror h is mathematically given as




Explanation:
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