Answer:
The minimum total speed is 11.2km/s
Explanation:
We are been asked to find the escape velocity.
Escape velocity is defined as the minimum initial velocity that will take a body(projectile)away above the surface of a planet(earth) when it's projected vertically upwards.
The formula to calculate the escape velocity is Ve = √2gR
For the earth g = 9.8m/s2 , R = 6.4*10^6
Substituting into the equation Ve = √2*9.8*6.4*10^6 = 11.2*10^3m/s
=11.2km/s
Answer:
The lone pair of electrons occupy more space because the electrostatic force becomes weaker.
Explanation:
When there is a bond pair of electrons in the 2 positively charged the atomic nuclei draw the electron density towards them, thereby reducing the bond diameter.
In the case of the lone pair, only 1 nucleus is present, and the enticing electrostatic force becomes weaker and the intensity of the electrons will be increases. Therefore, the lone pair occupies more space than the pair of bonds.
Answer:
weight
Explanation:
weight is measurd in newtons (N)
Answer:
C) 4.0026 amu
Explanation:
Helium (He) is the 2nd element on the Periodic Table.
It's neutral atom has 2 protons and 2 electrons.
It is in the 1st period and the 18th row.
It is also a Noble gas.
The magnitude of static friction is
<em>f</em> = <em>mv</em> ²/<em>r</em>
(i.e. the net force acting on the car parallel to the road points toward the center of the curve)
while the net vertical force must be
∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0
because the car is otherwise in equilibrium. Then
==> <em>n</em> = <em>mg</em>
==> <em>f</em> = <em>µn</em> = <em>µmg</em> = <em>mv</em> ²/<em>r</em>
==> <em>µ</em> = <em>v</em> ²/(<em>rg</em>)
We have
<em>v</em> = 101 km/h ≈ 28.1 m/s
<em>r</em> = 110 m
<em>g</em> = 9.80 m/s²
so that
<em>µ</em> = (28.1 m/s)² / ((110 m) <em>g</em>) ≈ 0.730