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2 years ago

Forest protect the soil from erosion ? True or False

Physics

2 answers:

Deffense [45]2 years ago

6 0

Answer:

True

Explanation:

Forest protect the soil from erosion because the trees in the forest hold the soil together not allowing it to erode.

Ivenika [448]2 years ago

4 0

Answer:

Forests helps in binding the soil together. Thus, prevent soil from erosion.

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A plant is thrown straight

olchik [2.2K]

The time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

<h3>How to calculate time?</h3>

The time taken for a motion to occur can be calculated using the following formula:

v² = u² - 2as

Where;

v = final velocity
u = initial velocity
s = distance
a = acceleration

8.84² = 0² + 2 × a × 7.01

78.15 = 14.02a

a = 5.57m/s²

V = u + at

8.84 = 0 + 5.57t

t = 1.59s

Therefore, the time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

Learn more about time at: brainly.com/question/13170991

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4 0

2 years ago

A girl of weight 600N sits on a 3-leg chair which weighs 60N. Each chair leg presses the floor in a circle with a diameter of 5c

Daniel [21]

Pressure = total force/total area

Total force = 660 Newton's

Total area:

Each leg contacts the floor with an area of πr^2=π(0.025m)^2=0.002m^2.

Total contact area for all 3 legs = 0.006 m^2.

Pressure = (660N) / (0.006 m^2)

= 110,000 N/m^2 = 110,000 Pascal's.

8 0

4 years ago

Suppose high tide is at midnight, the water level at midnight is 3 m, and the water level at low tide is 0.5 m. Assuming the nex

aev [14]

We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is

$t=10.0hours$

From the Question we are told that

Maximum height $h_{max}=3m$

Minimum height $H_{min}=0.5m$

Time for next high tide will occur $T=12 hours =>720 min$

Generally Average Height

$h_{avg}=\frac{3+0.5}{2}\\\\h_{avg}=1.75$

Therefore determine Amplitude to be

$A=h_{max}=j_{avg}\\\\A=3-1.75\\\\A=1.25$

Generally, the equation for Time is mathematically given by

At t=0

$h(x)=Acos(Bx)+h_{avg}$

Where

$B=\frac{2\pi}{P}\\\\B=\frac{2\pi}{720}\\\\B=8.73*10^{-3}$

Therefore

$h(t)=Acos8.73*10^{-3}(t)+h_{avg}$

Hence the Time at $T=1.125$ is

$1.125(t)=1.25cos(8.73*10^{-3})(t)+1.75$

$-0.1249t=1.75$

$t=10.0hours$

For more information on this visit

brainly.com/question/22361343

5 0

3 years ago

A child on a playground swings through a total of 32°. If the displacement is equal on each side of the equilibrium position, wh

sashaice [31]

Let L = length of the swing.

Let the lowest position of the swing be the reference point.
Therefore in the lowest position,
The height of the swing = 0,
The support for the swing is at height = L.

At 32° swing relative to the vertical,
The height of the swing is
A = L - Lcos(32°) = L[1 - cos(32°)] = 0.152L

Answer:
The amplitude is 0.152*L, where L = length of the swing.

6 0

4 years ago

A large group of people get together. each one rolls a die 180 times, and counts the number of 1's. about what percentage of the

Arte-miy333 [17]

<span>Around 99% - 100%. This is because a die is six sided, which gives the odds of a one coming up being roughly 17% independent of every roll. 17% of 180 trials comes out to 30-31 times a one will show up every 180 trials. This puts you right in the middle of the 15-45 range which means that somebody will almost ALWAYS reach 15-45 one's in a trial of 180 rolls.</span>

5 0

3 years ago