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Fiesta28 [93]
3 years ago
15

What is a vector? Please help!

Physics
1 answer:
Len [333]3 years ago
4 0
A quantity having direction as well as magnitude,especially as determining the position of one point in space relative to another.
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Are porkaryotic cells bigger or smaller than eukaryotic cells
Anna11 [10]
The prokaryotic cells are indeed smaller than the eularyotic cells.
Eukaruotic cell size -10-100um
Prokaryotic cell size - 1-10 um
8 0
4 years ago
A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m ​ 14, start fraction, start text, m, en
Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

​

 

=

Change in time

Change in velocity

​

=

Δt

v

f

​

−v

i

​

​

​

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

​

v, start subscript, f, end subscript, initial velocity v_iv

i

​

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

​

 

=

Δt

v

f

​

−v

i

​

​

=

3.5s

−21

s

m

​

−(−14

s

m

​

)

​

=−2.0

s

2

m

​

​

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

​

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0
3 years ago
A metal ball of specific heat capacity 400 joule per kgper celsius is allowed to fall from a height of 100 metre .If the ball on
ExtremeBDS [4]
First we'll calculate the energy it posesses

G.P.E = mgh = 0.2 * 10 * 100 = 200 J

Now we'll calculate the temperature rise

Q = m * c * (t2 - t1)
Q/(m * c) = t2-t1
t2 = Q/(m * c) + t1 = 200/(0.2 * 400) + 0 = <span>2.5 C</span>
7 0
3 years ago
A particle initially located at the origin has an acceleration of a=3jm/s^2 and an initial velocity of Vi=5im/s.
-BARSIC- [3]

Given the particle's acceleration is

\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath

with initial velocity

\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath

and starting at the origin, so that

\vec r(0) = \vec 0

you can compute the velocity and position functions by applying the fundamental theorem of calculus:

\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du

\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du

We have

• velocity at time <em>t</em> :

\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}

• position at time <em>t</em> :

\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}

8 0
3 years ago
A constant force of 4.0 N acts on a variety of objects. The greatest acceleration will occur in the object that has
zaharov [31]
In the object that has, the least inertia.
8 0
3 years ago
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