What is the magnitude of the electric field at a point that is 0.5m to the right of a small sphere with a net charge of -6.0x10-
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Answer:
The electric field is
Explanation:
Given that,
Radius = 2.00 cm
Number of turns per unit length
Current
We need to calculate the induced emf
Where, n = number of turns per unit length
A = area of cross section
=rate of current
Formula of electric field is defined as,
Where, r = radius
Put the value of emf in equation (I)
....(II)
We need to calculate the rate of current
....(III)
On differentiating equation (III)
Now, put the value of rate of current in equation (II)
Hence, The electric field is