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Aneli [31]
4 years ago
12

Why don't the planets move exactly along the ecliptic?

Physics
1 answer:
AVprozaik [17]4 years ago
6 0
As seen from the Earth, the Sun, Moon, and planets all appear to move along the ecliptic. ... Unlike the Sun, however, the planets don't always move in the same direction along the ecliptic. They usually move in the same direction as the Sun, but from time to time they seem to slow down, stop, and reverse direction!

Because of various events in their (unknown) past history that resulted in deviations from the theoretical orbit. That formed in the plain of the ecliptic.

Capturing a large passing comet or asteroid might do it.
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3. Which planet, other than Earth, is confirmed to have water on it?
Nadusha1986 [10]
Mars.

Water exists as small amounts of ice on Mars and as water vapor. It is suspected that Mars used to have flowing water on it, but that there is none left now.
8 0
3 years ago
Two equal forces are applied to a door. The first force is applied at the midpoint of the door, the second force is applied at t
Orlov [11]

Answer:

D) the second at the doorknob

Explanation:

The torque exerted by a force is given by:

\tau = Fdsin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the centre of rotation

\theta is the angle between the direction of the force and d

In this problem, we have:

- Two forces of equal magnitude F

- Both forces are perpendicular to the door, so \theta=90^{\circ}, sin \theta=1

- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force

--> therefore, the 2nd force exerts a greater torque

4 0
3 years ago
A woman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s abo
Charra [1.4K]

Explanation:

It is given that,

Mass of the woman, m₁ = 52 kg

Angular velocity, \omega=0.47\ rev/s=2.95\ rad/s

Mass of disk, m₂ = 118 kg

Radius of the disk, r = 3.9 m

The moment of inertia of woman which is standing at the rim of a large disk is :

I={m_1r^2}

I={52\times 3.9^2}

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

I_2=\dfrac{m_2r^2}{2}

I_2=\dfrac{118\times (3.9)^2}{2}

I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

I=I_1+I_2

I=790.92+897.39

I = 1688.31 kg-m²

The angular momentum of the system is :

L=I\times \omega

L=1688.31 \times 2.95

L=4980.5\ kg-m^2/s

So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.

8 0
3 years ago
What is the best example of a compound machine A ax. B ramp. C car D screw
liberstina [14]

Answer: I believe the answer is C

Explanation:

Cars are composed of hundreds of simple machines

3 0
3 years ago
Read 2 more answers
You are driving to the grocery store at 18 m/s. You are 120 m from an intersection when the traffic light turns red. Assume that
andrew-mc [135]

Answer:

11.64225 m

Explanation:A = 45 m/s – 15m/s / 6s  

A = 5m/s^2

8 0
4 years ago
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