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3 years ago

Why don't the planets move exactly along the ecliptic?

1 answer:

6 0

As seen from the Earth, the Sun, Moon, and planets all appear to move along the ecliptic. ... Unlike the Sun, however, the planets don't always move in the same direction along the ecliptic. They usually move in the same direction as the Sun, but from time to time they seem to slow down, stop, and reverse direction!

Because of various events in their (unknown) past history that resulted in deviations from the theoretical orbit. That formed in the plain of the ecliptic.

Capturing a large passing comet or asteroid might do it.

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When light travels through a small hole, it appears to an observer that the light spreads out, blurring the outline of the hole.

Scilla [17]

wave theory

this observation supports the theory of light as a wave

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3 years ago

Which kind of intermolecular force attracts the stearate ion to the oil drop?

Alchen [17]

The intermolecular force attracts of the stearate ion in the oil drop.

<u>Explanation:</u>

Dispersion force is the intermolecular force that attracts the stearate ion to the oil drop. The weak force with temporary dipoles. This force is referred to as induced dipole attraction.
The Dispersion is meant as an electron in two atoms occupies the position and this force is called induced dipole attraction.
The Dispersion force depends on the atomic and molecular weight of the material.

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3 years ago

If you are trying to hit a baseball as far as possible, you would want to:

skelet666 [1.2K]

Apply a large force over a short time

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3 years ago

The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the c

maria [59]

To solve this problem we will start using the concepts related to the electric field, from there we will find the load exerted on the body. Through this load it will be possible to make a sum of forces in balance to find the load that a human supports. Finally with these values it will be possible to find the repulsive force. We will proceed as follows,

The electric field is

$E= \frac{kQ}{R^2}$

Here,

k = Coulomb's Constant

Q = Charge

R = Distance (At this case from the center of mass of the earth to the surface)

Rearranging to find the charge,

$Q = \frac{ER^2}{k}$

Replacing,

$Q = frac{(150)(6.38*10^6)}{8.99*10^9}$

$Q = 6.79*10^5 C$

Since the electric field is directed towards the center of earth, the charge is negative.

PART A) Once the load is found we can proceed to apply the balance of Forces, for which the electrostatic force must be equivalent to the weight, this in order to satisfy the balance, therefore

$F_w = F_e$

$mg = \frac{kQq}{R^2}$

Replacing,

$(62)(9.8) = \frac{(8.99*10^9)(q)(-6.79*10^5)}{(6.38*10^6)^2}$

Solving for q,

$q = -4.056C$

PART B) Finally using the given distance and the values of the found load we can find the repulsive Force, which is

$F =\frac{kq^2}{d^2}$

$F = \frac{(8.99*10^9)(-4.056)^2}{110^2}$

$F = 1.22*10^7N$

PART C) The answer is no. According to the information found, we can conclude that traveling through an electric field is not viable because there is a repulsive force of great magnitude acting on the body.

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3 years ago

Fission fusion worksheet answers

fredd [130]

Http://tomschoderbekchem.blogspot.com/2014/09/nuclear-fission-and-fusion-worksheet.html

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3 years ago