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2 years ago

Make the equation 28 x 1/7 = 4 into a division equation PLEASE ANSWER FAST!!!!

Mathematics

1 answer:

Minchanka [31]2 years ago

7 0

4 divided by 1/7 = 28 i believe. sorry if i’m wrong

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Step-by-step explanation:

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2 years ago

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Dmitry_Shevchenko [17]

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2 years ago

Please help me find what y equals i need help, thank you so much, god bless you.

il63 [147K]

Answer:

Step-by-step explanation:

2(4)=8

8+7=15

hope this helped, have a blessed day!

4 0

2 years ago

Read 2 more answers

A girl is flying a kite with a 120ft string attached to the ground is flying directly Selena’s head is standing 24 ft from where

SashulF [63]

Answer:

111.58 feet

Step-by-step explanation:

Given that the length of the string (AB in the attached diagram) is 120 feet.

Selena (at point D) is standing 24 feet from point A, where the kite is attached to the ground.

Since the kite is directly above Selena's head, the problem forms a right triangle.

Using Pythagoras theorem

$|AB|^2=|BD|^2+|AD|^2\\120^2=|BD|^2+24^2\\|BD|^2=120^2-24^2\\|BD|^2=13824\\|BD|=\sqrt{13824} \\|BD|=117.58$ ft$

Serena's height (CD=6 feet)

The distance of the kite above her head is BC in the drawn diagram.

Therefore:

|BD|=|BC|+|CD|

117.58=|BC|+6

|BC|=117.58-6

|BC|=111.58 feet

The kite is approximately 111.58 feet above Selena's head/

5 0

2 years ago

A major metropolitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers.

Tpy6a [65]

Answer: $(0.36845,\ 0.43155)$

Step-by-step explanation:

Let p be the population proportion of readers who would like more coverage of local news.

As per given , we have

sample size :=1600

sample proportion : $\hat{p}=40\%=0.40$

The confidence interval for population proportion is given by :-

$\hat{p}\pm z^* \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

From z-table ,

For 99% confidence interval the z-value is 2.576.

Substitute all the values in the above formula , we get

The 99% confidence interval for the proportion of readers who would like more coverage of local news as

$0.40\pm(2.576) \sqrt{\dfrac{0.40(1-0.40)}{1600}}$

$0.40\pm(2.576) \sqrt{\dfrac{0.24}{1600}}$

$0.40\pm(2.576) \sqrt{0.00015}$

$0.40\pm(2.576) (0.0122474487139)$

$0.40\pm0.03155$

$(0.40-0.03155,\ 0.40+0.03155)=(0.36845,\ 0.43155)$

Hence, the 99% confidence interval for the proportion of readers who would like more coverage of local news is $(0.36845,\ 0.43155)$ .

5 0

2 years ago