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lubasha [3.4K]
3 years ago
11

A sprinter runs 50m. You are given a stopwatch. Describe how you would measure: 1. the average speed of the sprinter over the en

tire 50m
2. the instantaneous speed of the sprinter when he crosses the finish line
Physics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

Explanation:

Distance = 50 m

1. To find the average speed, first start the stop watch as the sprinter starts running and then stop it when he reaches the finish line.

Now note the time taken by the sprinter to run for 50 m.

The average speed of the sprinter is defined as the ratio of total distance covered to the total time taken.

Average speed = total distance / total time

2. To find the instantaneous speed, check the seed of the sprinter as he is at the finish line.

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(15 points) (Asap!!)<br>In what two ways can you increase the elastic potential energy of a spring?
adelina 88 [10]
Hello There

Answers: T<span>he elastic potential energy can be increased by: </span>

<span>1) Getting a spring with a higher spring constant</span>

<span>2) Increasing the length at which the spring is compressed. 

Reasons: Getting a stronger spring makes it stronger which equals more energy. While increasing the compression on the spring, increases the stored energy which makes it more powerful when its released

I hope this helps
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5 0
2 years ago
Read 2 more answers
At which temperature does the molecules of an object stop moving?
PilotLPTM [1.2K]

Answer:

at the melting point and boiling point

Explanation:

the heat abdorbed is used to break down the forces holding the particles together to allow it to change its state

7 0
2 years ago
Explain why ice floats in water. Explain why ice floats in water. Steam is more dense than water. Ice is the same density as wat
Pani-rosa [81]

Hey how's your day going

I hope after I answer that you understand and don't just paste my answer into your assignment!!! (<- read!!!)

Answer \|/

             

Ice is less dense than water.

Reason why \|/

                   

When water freezes the molecules inside completely stop moving (They still vibrate but don't change their position much). In doing so, they spread out a touch which makes it less dense than liquid water. So ice floats

3 0
2 years ago
Consider two diffraction gratings with the same slit separation. The only difference between the two gratings is that one gratin
kobusy [5.1K]

Answer:

True The grid with more slits gives more angle separation increases

True. The grating with 10 slits produces better-defined (narrower) peaks

Explanation:

Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is

      d sin θ = m λ

where d is the distance between slits or lines, m the order of diffraction and λ the wavelength.

For network with 5 slits

      d = 1/5 = 0.2

For the network with 10 slits

      d = 1/10 = 0.1

let's calculate the separation (teat) for each one

      θ = sin⁻¹ (m λ / d)

for 5 slits

     θ₅ = sin⁻¹ (m λ 5)

for 10 slits

     θ₁₀ = sin⁻¹ (m λ 10)

we can appreciate that for more slits the angle increases

the intensity of a series of slits is

       I = I₀ sin²2 (N d/2) / sin² d/2)

when there are more slits (N) the peaks have greater intensity and are more acute (half width decreases)

let's analyze the claims

False

True The grid with more slits gives more angle separation increases

False

True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases

False

5 0
3 years ago
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
2 years ago
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