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3 years ago

How much kinetic energy does an object have that is moving at a rate of 30 m/s and has a mass of 4000 kg ?

Physics

1 answer:

DaniilM [7]3 years ago

3 0

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ$

So, the required kinetic energy is equal to 1800 kJ.

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Answer:

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Explanation:

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3 years ago

Student swings a small rubber stopper attached to a string over her head in a horizontal, circular path. The string is 1.50 mete

harkovskaia [24]

Answer:

v = 18.84 m/s

Explanation:

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It means, its frequency is 2 circles every second.

Let we need to find the average speed of the rubber stopper. It can be calculated as follows :

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4 0

3 years ago

A 100 kg cart on a roller coaster has 1800J of kinetic energy. How fast is it going?<br> KE= 1/2mv2

34kurt

Answer:

the speed is equal to 6 m/s

Explanation:

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3 years ago

A ball is dropped from rest at the top of a 6.10 m

natita [175]

Answer:

n = 5 approx

Explanation:

If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back

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and

$\frac{v_1}{v} = \sqrt{\frac{h_1}{6.1} }$

h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

$e = \sqrt{\frac{h_1}{6.1} }$

$e = \sqrt{\frac{h_2}{h_1} }$

So on

$e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }$

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Taking log on both sides

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n / 2 = 2.4

n = 5 approx

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