The problem corresponds to the motion of a projectile (the salmon), with initial speed 
, initial direction 
and vertical acceleration 
downward. The two equations which gives the horizontal and vertical position of the salmon at time t are
(1)
(2)
We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.
Solving eq.(1) for t:
And substituting this expression of t into eq.(2), we get the following expression for :
And substituting the numbers into the equation, we find
If you match the amount of static friction that can be generated when the object is at rest, it will not move because there is zero force the force has to be greater that the static friction in order to have it include motion. But if there was any more force will cause acceleration otherwise if it was lower force it will deceleration.
It depends on the type of question, mechanical condition and given values,
You can use the formula,
Coefficient of kinetic friction = Force of Kinetic friction / Normal force (perpendicular to contacting surfaces)
Hope this helps!
Answer:
1.28 m, 14 m/s
Explanation:
At the maximum height, the velocity is 0.
Given:
a = -9.8 m/s²
v₀ = 5.00 m/s
v = 0 m/s
x₀ = 0 m
Find:
x
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (5.00 m/s)² + 2(-9.8 m/s²) (x - 0 m)
x = 1.28 m
The maximum speed is at the bottom of the well.
Given:
a = -9.8 m/s²
v₀ = 5.00 m/s
x₀ = 0 m
x = -8.5 m
Find:
v
v² = v₀² + 2a(x - x₀)
v² = (5.00 m/s)² + 2(-9.8 m/s²) (-8.5 m - 0 m)
v = -13.8 m/s
Rounded to 2 sig-figs, the maximum speed is 14 m/s.
Explanation:
1ml = 2.7g
Xml = 1.5g
Divide 1.5 by 2.7 to find X.
Obviously, since 1.5 is less than 2.7, you know the answer will be less than 1.
(it’s .5555555555)
