Answer:
a = 0.5195 m/s²
θ = 9.997º ≈ 10º
Explanation:
We apply Newton's 2nd Law as follows:
∑ Fx = m*ax
∑ Fy = m*ay
Then we have
∑ Fx = F₁x + F₂x = m*ax ⇒ 600*Cos 40º + 600*Cos (-20º) = 2000*ax
⇒ ax = 0.5117 m/s²
∑ Fy = F₁y + F₂y = m*ay ⇒ 600*Sin 40º + 600*Sin (-20º) = 2000*ay
⇒ ay = 0.0902 m/s²
the magnitude of the acceleration of the barge is
a = √(ax² + ay²) = √((0.5117 m/s²)² + (0.0902 m/s²))= 0.5196 m/s²
and the direction is
θ = Arctan (ay / ax) = Arctan (0.0902 / 0.5117) = 9.997º ≈ 10º
Answer
7 is d ii is a iii is d
4 is x is 52 and y is 0 = 68
5 is x is 0 = 145 and y is 128
6 is a
1 is 10.20
2 is 151 and 5010
3 is < is 0 and I is y
9 is 3.0 and 2.0
hope this helps
Answer:
elative magnitude of the two forces is the same and they are applied in a constant direction.
Explanation:
Newton's second law states that the sum of the forces is equal to the mass times the acceleration
∑ F = m a
in this case there are two forces on the x axis
F_applied - fr = 0
since they indicate that the velocity is constant, consequently
F_applied = fr
the relative magnitude of the two forces is the same and they are applied in a constant direction.
