All categories

3 years ago

What is also known as a ferromagnetism

Physics

1 answer:

Aleks [24]3 years ago

6 0

Answer:

Iron, nickel, cobalt and some of the rare earths (gadolinium, dysprosium) exhibit a unique magnetic behavior which is called ferromagnetism because iron (ferrum in Latin) is the most common and most dramatic example.

You might be interested in

Starting from the front door of your ranch house, you walk 50.0m due east to your windmill, and then you turn around and slowly

juin [17]

Answer:

velocity = 0.3m/s

speed = 1.21 m/s

Explanation:

The total time it takes to get from the front door to the bench is

t = 27 + 39 = 66 seconds

The net displacement from the front door to the bench is the distance from the front door to the windmill subtracted by the distance from the windmill to the bench

s = 50 - 30 = 20 m

So the average velocity is net displacement divided by total time

v = s / t = 20 / 66 = 0.3 m/s

The total distance from the front door to the bench is the sum of distance from the front door to the windmill and the distance from the windmill to the bench

S = 50 + 30 = 80 m

So the average speed is total distance divided by total time

v = s / t = 80 / 66 = 1.21 m/s

8 0

3 years ago

How does microwave technology cook food?

Y_Kistochka [10]

Answer:

By heating all the water molecules which changes the thermal energy of the food

Explanation:

3 0

2 years ago

A parachutist of mass 20.1 kg jumps out of an airplane at a height of 662 m and lands on the ground with a speed of 7.12 m/s. Th

Klio2033 [76]

Answer:

$1.30\cdot 10^5 J$

Explanation:

The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.

The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:

$E_i=mgh$

where

m = 20.1 kg is his mass

$g=9.8 m/s^2$ is the acceleration due to gravity

h = 662 m is the initial heigth

The final mechanical energy (at the bottom) is equal to his kinetic energy:

$E_f=\frac{1}{2}mv^2$

where

v = 7.12 m/s is the final speed of the parachutist

Therefore, the energy lost due to air friction is:

$\Delta E=E_i-E_f=mgh-\frac{1}{2}mv^2=(20.1)(9.8)(662)-\frac{1}{2}(20.1)(7.12)^2=1.30\cdot 10^5 J$

4 0

4 years ago

A vector in the xy plane has components -14.0 units in the x-direction and 30.0 units in the y-direction. What is the magnitude

OverLord2011 [107]

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

We would calculate the magnitude by applying pythagorean theorem:

$\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}$

$\longrightarrow \sf{Magnitude = 33.12}$

$\longrightarrow \sf{The \: vector \: is \: (- 14, 30)}$

The angle between two vectors is given by the formula:

$\sf{\longrightarrow \small \cos \emptyset = \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }$

In two dimensional, the x axis of vector form is:

$\small\sf{\longrightarrow (b1, b2) = (1, 0) }$

$\sf{\longrightarrow \small \cos \: \emptyset = \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }$

$\small\longrightarrow \sf{ \dfrac{14}{33.12} }$

$\small\longrightarrow \sf{\emptyset \: = arcCos (\dfrac{ - 14}{33.12} )}$

$\small\longrightarrow \sf{\emptyset= 115^\circ}$

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\small\bm{The \: angle \: between \: the \: vector \: }$

$\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}$

6 0

2 years ago

A student has to work the following problem: A block is being pulled along at constant speed on a horizontal surface a distance

brilliants [131]

Answer:

The answer cannot be found until it is known whether q is greater than, less than, or equal to 45°.

Explanation:

Since block moves with constant speed

So, frictional force

f = FCosq

Work done by friction

W = - fd

W = - fd Cos q

The answer may be greater or less than - fdSinq. It depends on the value of q which is less than, or equal to 45°.

6 0

3 years ago