Most as long the hypothesis is a good answer and can be answered
Transformer
<u>Explanation:</u>
A transformer is a device with two or more magnetically coupled windings. A time varying current in one coil (primary winding) generates a magnetic field which induces a voltage in the other coil (secondary winding). Transformers are capable of either increasing or decreasing the voltage and current levels of their supply, without modifying its frequency, or the amount of electrical power being transferred from one winding to another via the magnetic circuit. There are two types of transformer:
1. Step up transformer - increases voltage
2. Step down transformer - decreases voltage
Answer:
E = q V B describes the electric field induced
E Proportional to V B
while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)
If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly
When V drops to zero the deflection must again be zero
So one would see a blip due to the deflection of the galvanometer
Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)
B always increases to a constant value because of the properties of the magnet.
Answer:
a circuit is a complete loop that carries a current in the form of electrons from negative to positive
Explanation:
The difference between current and circuit is that a circuit is a complete loop that carries a current in the form of electrons from negative to positive
.
In a circuit, there are difference elements or components such as the battery, wire, resistor. The goal of a circuit arrangement is to completely carry current from one end to another.
The current is the quantity of charge that flows within the circuit per unit of time.
So, the battery supplies the electromotive force to move the current round the circuit.
Answer:
ΔK.E = 14 nJ
Explanation:
Solution:
- The charge that moves under the influence of an Electric Field produced between a potential difference (V) stores electric potential energy U within that is converted to kinetic energy.
- We will use conservation of energy on the system that contains the charged particle with charge q loses its electric potential energy U as it moves towards positively charged object that converts into a gain in Kinetic energy of the charged particle ΔK.E:
ΔK.E = U
Where,
U = V*q
ΔK.E = V*q
ΔK.E = (7*10^-6)*(2*10^-3)
ΔK.E = 14 nJ
- The gain in kinetic energy is 14 nJ.
